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Question #43151
The Question
An LCR series circuit contains an inductor , a capacitor , and a non-linear resistor across which the voltage drop is given by , where is the current and is a positive constant. The circuit is driven by an AC voltage source , where is the resonant frequency. Assume that the steady-state current can be approximated as purely sinusoidal at the fundamental frequency .
A separate mechanical damped harmonic oscillator of mass and spring constant is subjected to a linear damping force , where is the velocity and is the damping constant. It is driven by an external force at its resonant frequency .
If the average power dissipated over one complete cycle in both systems is equal, which of the following expressions gives the equivalent linear damping constant ?
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
Average Power over Cycle|Driven Oscillations and Resonance|Calculus: Definite Integration
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to evaluate average power dissipation in driven non-linear oscillators by integrating over a full period, rather than incorrectly equating instantaneous peak values.
A common trap is to assume that the peak voltage equals the peak resistive drop (), which ignores the generation of higher harmonics and violates energy balance over a cycle.
By requiring the student to equate the average power supplied () to the average power dissipated (), the problem enforces the use of the first harmonic approximation.
Furthermore, it tests the exact mapping of energy dissipation between an electrical LCR circuit and a mechanical damped oscillator, ensuring dimensional and physical consistency.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Alternating Current - Class 12 |
| Concept | Average Power over Cycle |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |