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Question #43165

Difficulty: 8/10 | 🟢 Free

The Question

A rigid non-conducting rod of length LL and negligible mass rotates in a horizontal plane about a frictionless vertical axis through one end (the pivot). A central hub at the pivot has a moment of inertia I0=mL2I_0 = m L^2. The system is given an initial angular velocity ω0\omega_0. A uniform vertical magnetic field BB is present everywhere. A small conducting bead of mass mm slides outward along the rod at a constant speed v0v_0 relative to the rod, starting from the pivot at t=0t=0. A fixed conducting plate of area AA is attached to the free end of the rod (r=Lr=L). The bead acts as the second plate of area AA, forming a parallel-plate capacitor with a time-varying gap L−r(t)L - r(t). To establish a potential difference, a thin conducting wire connects the pivot to the bead, and another separate thin conducting wire connects the pivot to the fixed end plate. Assume the wires have negligible mass, the electrical energy stored is negligible compared to the kinetic energy, and fringing effects are ignored. What is the magnitude of the displacement current in the gap at the instant the bead passes the midpoint of the rod (r=L/2r = L/2)?

Options

  • A.

    225ϵ0ABω0v0\frac{2}{25} \epsilon_0 A B \omega_0 v_0

  • B.

    12ϵ0ABω0v0\frac{1}{2} \epsilon_0 A B \omega_0 v_0

  • C.

    425ϵ0ABω0v0\frac{4}{25} \epsilon_0 A B \omega_0 v_0

  • D.

    14ϵ0ABω0v0\frac{1}{4} \epsilon_0 A B \omega_0 v_0

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Maxwell's Correction to Ampere's Law|Motional EMF in Rotating Rods|Variable Mass Systems

Why This Question Is Tricky

Common Mistakes

This question tests multiple layers of JEE Advanced concepts by coupling electromagnetism with rigid body dynamics.

The primary trap is neglecting the Conservation of Angular Momentum; students often assume the angular velocity ω\omega remains constant because no external torque is applied, forgetting that the radial migration of the bead changes the system's moment of inertia.

Assuming constant ω\omega leads directly to Option B.

Additionally, the problem requires recognizing that the motional EMF and the time-varying capacitance mathematically couple to cancel the (L−r)(L-r) term, simplifying the charge equation.

Finally, it tests the rigorous application of the chain rule for displacement current Id=dQdt=dQdrdrdtI_d = \frac{dQ}{dt} = \frac{dQ}{dr}\frac{dr}{dt}, where a simple quotient rule mistake will lead to incorrect prefactors.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectromagnetic Waves - Class 12
ConceptMaxwell's Correction to Ampere's Law
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree