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Question #43165
The Question
A rigid non-conducting rod of length and negligible mass rotates in a horizontal plane about a frictionless vertical axis through one end (the pivot). A central hub at the pivot has a moment of inertia . The system is given an initial angular velocity . A uniform vertical magnetic field is present everywhere. A small conducting bead of mass slides outward along the rod at a constant speed relative to the rod, starting from the pivot at . A fixed conducting plate of area is attached to the free end of the rod (). The bead acts as the second plate of area , forming a parallel-plate capacitor with a time-varying gap . To establish a potential difference, a thin conducting wire connects the pivot to the bead, and another separate thin conducting wire connects the pivot to the fixed end plate. Assume the wires have negligible mass, the electrical energy stored is negligible compared to the kinetic energy, and fringing effects are ignored. What is the magnitude of the displacement current in the gap at the instant the bead passes the midpoint of the rod ()?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
Maxwell's Correction to Ampere's Law|Motional EMF in Rotating Rods|Variable Mass Systems
Why This Question Is Tricky
Common Mistakes
This question tests multiple layers of JEE Advanced concepts by coupling electromagnetism with rigid body dynamics.
The primary trap is neglecting the Conservation of Angular Momentum; students often assume the angular velocity remains constant because no external torque is applied, forgetting that the radial migration of the bead changes the system's moment of inertia.
Assuming constant leads directly to Option B.
Additionally, the problem requires recognizing that the motional EMF and the time-varying capacitance mathematically couple to cancel the term, simplifying the charge equation.
Finally, it tests the rigorous application of the chain rule for displacement current , where a simple quotient rule mistake will lead to incorrect prefactors.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Electromagnetic Waves - Class 12 |
| Concept | Maxwell's Correction to Ampere's Law |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |