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Question #43196
The Question
A light ray enters a non-homogeneous transparent medium at the origin of an -coordinate system. The -axis points vertically downwards into the medium, and the -axis lies along the surface boundary. The refractive index of the medium varies with depth as for , where and . The ray enters the medium at an angle with respect to the positive -axis. The ray curves continuously, reaches a maximum depth, and eventually undergoes total internal reflection to return to the surface . What is the total horizontal distance traveled by the ray when it emerges back at the surface?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Variable_Constraint
Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.
Concepts Behind This Question
Total Internal Reflection (TIR)|Gravitational Field Variation|Integration
Why This Question Is Tricky
Common Mistakes
This question tests the application of Fermat's Principle and generalized Snell's Law in a medium with a continuous refractive index gradient.
A common trap is treating the gradient as discrete slabs and failing to construct the correct differential equation for the ray path ().
Students often incorrectly assume or fail to account for the symmetry of the trajectory, missing the factor of 2 for the return journey (leading to option B).
Advanced students can bypass the integration by recognizing the optomechanical analogy: the ray path is mathematically identical to the parabolic trajectory of a projectile in a uniform gravitational field, where the effective acceleration is derived from the gradient of .
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Ray Optics and Optical Instruments - Class 12 |
| Concept | Total Internal Reflection (TIR) |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |