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Question #43241
The Question
A thin transparent film of thickness and refractive index is coated on a thick glass substrate of refractive index . The film is in contact with air (). A plane light wave of wavelength (in vacuum) is incident on the film from air at an angle of incidence . The incident light is p-polarized (electric field in the plane of incidence).
The amplitude reflection coefficient for p-polarized light moving from medium to is given by , where and are the angles of incidence and refraction, respectively. A positive corresponds to a phase shift of , while a negative corresponds to a phase shift of .
Find the minimum non-zero thickness of the film for which the reflected light undergoes perfectly destructive interference.
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
Phase and Path Difference|Snell’s Law Vector Form|Vector Cross-Products
Why This Question Is Tricky
Common Mistakes
This question tests the student's understanding of orientation-dependent phase shifts in thin film interference, specifically for p-polarized light.
A common trap is blindly applying the standard scalar rule that 'reflection from a denser medium always yields a phase shift'.
Since , students incorrectly assume a shift at both surfaces, leading to a net phase shift of and the incorrect condition (Option B).
However, for p-polarized light incident at an angle greater than the Brewster angle, the reflection coefficient becomes negative, resulting in a phase shift at the top surface.
This restores the net phase difference, fundamentally altering the interference condition.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Wave Optics - Class 12 |
| Concept | Phase and Path Difference |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |