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Question #43246
The Question
A free, excited atom of mass is initially at rest at a distance from a double-slit apparatus with slit separation . It emits a single photon of wavelength which passes through the slits and is detected on a screen at a distance from the slits. An experimenter measures the transverse recoil velocity (parallel to the slit separation) of the atom to an accuracy in an attempt to determine which slit the photon passed through ( is Planck's constant). Assuming the atom's transverse position and momentum satisfy the minimum uncertainty condition , what is the resulting minimum uncertainty in the position of the central interference maximum on the screen?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Young's Double Slit Geometry|Wave-Particle Duality Constraint|Recoil of Atom
Why This Question Is Tricky
Common Mistakes
This question tests the synthesis of quantum mechanics (Heisenberg's Uncertainty Principle) with classical wave optics (Young's Double Slit Experiment).
Students often treat the photon source as a classical, static point.
By introducing a measurement of the atom's recoil to obtain 'which-path' information, the problem forces the application of HUP to the macroscopic source.
The primary trap is failing to apply the geometric magnification factor () that relates the source's spatial uncertainty to the smearing of the interference pattern on the screen, leading to Option C.
Another common mistake is misapplying the HUP constant as instead of , leading to Option B.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Wave Optics - Class 12 |
| Concept | Young's Double Slit Geometry |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |