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Question #43257
The Question
An electron of mass (in kg) and charge (in C) orbits a massive nucleus in an elliptical orbit. The orbit has a semi-major axis (in m), eccentricity (dimensionless), and time period (in s). The nucleus is located at one of the foci of the ellipse. What is the magnitude of the instantaneous magnetic field (in T) produced by the electron at the nucleus when the electron is at its apocenter (farthest point from the nucleus)? Assume non-relativistic motion and vacuum permeability (in ).
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Magnetic Dipole Moment of Revolving Electron|Kepler’s Second Law (Areal Velocity)|Vector Cross-Product
Why This Question Is Tricky
Common Mistakes
This question tests the misapplication of the average current formula to calculate instantaneous magnetic fields in non-circular orbits.
Students often fall into the trap of assuming the electron acts as a steady circular current loop of radius , leading to the incorrect Biot-Savart application (Option B).
Another common error is assuming a constant average orbital speed (Option C).
The correct physical framework requires recognizing that while the linear and angular velocities fluctuate, Kepler's Second Law dictates that the areal velocity remains constant.
This intrinsically links the instantaneous magnetic field to the conserved orbital angular momentum, demanding a derivation from fundamental point-charge electrodynamics rather than macroscopic steady-current approximations.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Magnetism and Matter - Class 12 |
| Concept | Magnetic Dipole Moment of Revolving Electron |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |