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Question #43277
The Question
A small, thin disk of volume made of a linear dielectric material with relative permittivity is placed in a non-uniform electric field . Let be the net electric force on the disk when its normal vector is parallel to the -axis, and be the force when is perpendicular to the -axis.
Similarly, an identical disk made of a linear paramagnetic material with relative permeability is placed in a non-uniform magnetic field . Let be the net magnetic force on the disk when its normal vector is parallel to the -axis, and be the force when is perpendicular to the -axis.
Assume the disk is small enough that the external fields and their gradients are uniform over its volume. Which of the following gives the correct ratios and ?
Options
- A.
and
- B.
and
- C.
and
- D.
and
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Magnetic Permeability and Susceptibility|Dielectric Slab Displacement|Power-Velocity Relationship
Why This Question Is Tricky
Common Mistakes
This question tests the misconception that the force on a dielectric or magnetic material in a field gradient depends only on the material properties or and the external field gradient, ignoring the geometry-dependent depolarization and demagnetization fields.
Students often blindly apply the formulas derived for slabs inserted parallel to the field (like in standard capacitor or solenoid problems) to all geometries.
By forcing a comparison between orientations, the question reveals that the boundary conditions ( continuous vs continuous) fundamentally alter the internal fields, leading to a or suppression factor when the object's normal is parallel to the external field.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Magnetism and Matter - Class 12 |
| Concept | Magnetic Permeability and Susceptibility |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |