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Question #43308
The Question
A toroidal inductor is constructed with a non-magnetic core of uniform height . The core is densely wound with turns of wire carrying a current . The inner boundary of the core is a cylinder of constant radius . The outer boundary of the core has a variable radius that depends on the azimuthal angle as: where is a positive dimensionless constant. Assuming the magnetic field inside the core at a distance from the central axis is given by , what is the self-inductance of this toroid?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Variable_Constraint
Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.
Concepts Behind This Question
Energy Stored in Inductor|Toroidal Solenoid Boundary Conditions|Infinite Wire vs. Finite Wire
Why This Question Is Tricky
Common Mistakes
This question tests the student's fundamental understanding of inductance by breaking the symmetry required for standard formulas.
The primary trap relies on students over-relying on the standard formula for a rectangular toroid, .
When faced with a variable outer radius , students often incorrectly substitute the maximum radius (), yielding Option B, or attempt to find an average radius, yielding Option D.
The rigorous physical approach requires recognizing that inductance is fundamentally a measure of magnetic energy storage per unit current squared ().
By forcing the integration of the magnetic energy density over a non-uniform volume, the question filters out students who treat inductance as a static table-lookup value rather than a field-energy derivative.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Electromagnetic Induction - Class 12 |
| Concept | Energy Stored in Inductor |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |