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Question #43355

Difficulty: 8/10 | 🟢 Free

The Question

A small coil of N=50N=50 turns, area A=200 cm2A=200 \text{ cm}^2, and internal resistance r=2 Ωr=2 \text{ }\Omega moves with a constant velocity v⃗=5i^ m/s\vec{v} = 5 \hat{i} \text{ m/s} along the x-axis. The coil is in a region of non-uniform magnetic field B⃗=βx2k^\vec{B} = \beta x^2 \hat{k}, where β=2 T/m2\beta = 2 \text{ T/m}^2 and k^\hat{k} is the unit vector pointing out of the page. Assume the coil dimensions are small enough that the magnetic field is uniform over its area at any instant. The coil is connected in series with a variable external resistor RR. The potential difference across RR is fed to a potentiometer circuit. The potentiometer consists of a wire of length L=1 mL=1 \text{ m} connected across an ideal 10 V10 \text{ V} DC source. The connections to the potentiometer are made such that a null point can only be obtained if the induced current in the moving coil is in the clockwise direction. If RR is set to extract maximum electrical power from the coil, at what position xx of the coil will a null point be observed on the potentiometer wire at a balancing length of l=50 cml = 50 \text{ cm}?

Options

  • A.

    +0.5 m+0.5 \text{ m}

  • B.

    −0.5 m-0.5 \text{ m}

  • C.

    +0.25 m+0.25 \text{ m}

  • D.

    −0.25 m-0.25 \text{ m}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Potentiometer Null Point|Maximum Power Transfer|Magnetic Flux Scalar Sign|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the synthesis of electromagnetic induction, DC circuits, and the Maximum Power Transfer theorem, with a lethal trap embedded in the sign convention of Faraday's Law.

Students frequently calculate the magnitude of the induced EMF and blindly solve for position, yielding two mathematical roots (x=±0.5 mx = \pm 0.5 \text{ m}).

However, they misapply or ignore Lenz's Law, failing to recognize that the polarity of the induced EMF flips as the coil crosses the origin.

Because a potentiometer can only balance a specific polarity, the physical constraint of a 'clockwise current' acts as a directional filter, invalidating the negative root.

Furthermore, forgetting the internal resistance matching condition (R=rR=r) leads to an incorrect voltage calculation, trapping students who assume the potentiometer balances the full EMF (leading to the 0.25 m0.25 \text{ m} options).

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterCurrent Electricity - Class 12
ConceptPotentiometer Null Point
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree