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Question #43484

Difficulty: 8/10 | 🟢 Free

The Question

The displacement-time (x−tx-t) graph of a particle of mass m=2.0 kgm = 2.0 \text{ kg} moving along the x-axis is described by the function x(t)=x01+(t/t0)2x(t) = \frac{x_0}{1 + (t/t_0)^2} for t≥0t \ge 0, where x0=4.0 mx_0 = 4.0 \text{ m} and t0=3.0 st_0 = 3.0 \text{ s}. The particle experiences a position-dependent conservative force F(x)F(x). Let xcx_c be the position where the x−tx-t graph changes its concavity. What is the effective spring constant keff=−dFdxk_{\text{eff}} = -\frac{dF}{dx} evaluated at x=xcx = x_c?

Options

  • A.

    1.0 N/m1.0 \text{ N/m}

  • B.

    −1.0 N/m-1.0 \text{ N/m}

  • C.

    0.0 N/m0.0 \text{ N/m}

  • D.

    83 N/m\frac{8}{3} \text{ N/m}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Graphical Concavity Significance|SHM Definition via Differential Equation|Effective Spring Constant

Why This Question Is Tricky

Common Mistakes

The question tests the student's ability to link kinematic graphical features (concavity) to dynamic properties (effective stiffness) in a non-linear system.

The primary trap is assuming that at the inflection point where acceleration (and thus net force) is zero, the effective spring constant must also be zero (keff=−F/x=0k_{\text{eff}} = -F/x = 0).

This misapplies the linear SHM relation F=−kxF = -kx to a non-linear regime.

Students must recognize that keffk_{\text{eff}} is the local gradient of the force curve (−dFdx-\frac{dF}{dx}), requiring them to express acceleration as a function of position xx before differentiating, rather than differentiating with respect to time.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMotion in a Straight Line - Class 11 Part 1
ConceptGraphical Concavity Significance
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree