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Question #43514

Difficulty: 8/10 | 🟢 Free

The Question

A satellite of mass mm is in a circular orbit of radius RR in the xyxy-plane around the Earth (mass MM, fixed at the origin of an inertial frame). The satellite's orbital angular velocity is ω=GM/R3\omega = \sqrt{GM/R^3}. At time t=0t=0, the satellite crosses the positive xx-axis.

A non-inertial reference frame S′S' translates relative to the Earth. The origin of S′S' coincides with the Earth's center at t=0t=0 and moves along the positive xx-axis with a constant acceleration a⃗s=a0i^\vec{a}_s = a_0 \hat{i} and zero initial velocity.

Calculate the work done strictly by the Earth's gravitational force on the satellite, as measured by an observer in frame S′S', during the time interval from t=0t=0 to t=π/ωt=\pi/\omega.

Options

  • A.

    00

  • B.

    −2mRa0-2m R a_0

  • C.

    2mRa02m R a_0

  • D.

    12ma02(πω)2\frac{1}{2} m a_0^2 \left(\frac{\pi}{\omega}\right)^2

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Orbital Velocity Energy Balance|Frame of Reference Dependency|Non-Uniform Acceleration Constraint

Why This Question Is Tricky

Common Mistakes

Students often mistakenly assume that because gravity is a conservative central force, the work it does is simply the negative change in potential energy (W=−ΔUW = -\Delta U).

Since the satellite is at a distance RR from the Earth at both t=0t=0 and t=π/ωt=\pi/\omega, they incorrectly conclude ΔU=0\Delta U = 0 and thus Wg′=0W_g' = 0 (Option A).

However, in the accelerating non-inertial frame S′S', the source of the gravitational field (the Earth) is moving.

This makes the gravitational potential explicitly time-dependent in S′S' (U(r⃗′,t)U(\vec{r}', t)), meaning the gravitational force acts as a non-conservative force in this frame.

The standard W=−ΔUW = -\Delta U relation fails, and the work must be calculated via explicit path integration of F⃗g⋅dr⃗′\vec{F}_g \cdot d\vec{r}', accounting for the frame's relative velocity.

Option D traps students who calculate the total change in kinetic energy (which includes the work done by the pseudo-force) instead of isolating the work done by gravity.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterGravitation - Class 11 Part 1
ConceptOrbital Velocity Energy Balance
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree