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Question #43518

Difficulty: 8/10 | 🟢 Free

The Question

A massive space station is in a circular orbit of radius r0r_0 (in m\text{m}) around a planet of mass MM (in kg\text{kg}). The station is tidally locked, rotating with a constant orbital angular velocity ω0=GMr03\omega_0 = \sqrt{\frac{GM}{r_0^3}} (in rad/s\text{rad/s}) to keep the same face towards the planet. Inside the station, a smooth straight tube is aligned along the radial direction. A payload of mass mm (in kg\text{kg}) is placed inside the tube at the equilibrium position r=r0r = r_0. It is connected to the station by a spring of force constant kk (in N/m\text{N/m}) and a damper providing a resistive force Fd=−bvrelF_d = -b v_{rel}, where vrelv_{rel} (in m/s\text{m/s}) is the radial velocity of the payload relative to the tube and bb (in kg/s\text{kg/s}) is the damping constant.

An engineer maps the small radial displacements xx of the payload to an equivalent electrical LL-CC-RR circuit equation Led2qdt2+Redqdt+1Ceq=0L_e \frac{d^2q}{dt^2} + R_e \frac{dq}{dt} + \frac{1}{C_e} q = 0. In this analogy, the displacement xx maps to charge qq, and the mass mm maps to inductance LeL_e. Assuming k>3mω02k > 3m\omega_0^2, what is the expression for the equivalent capacitance CeC_e?

Options

  • A.

    1k−3mω02\frac{1}{k - 3m\omega_0^2}

  • B.

    1k+mω02\frac{1}{k + m\omega_0^2}

  • C.

    1k\frac{1}{k}

  • D.

    1k−mω02\frac{1}{k - m\omega_0^2}

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Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Geostationary Satellite Constraints|L-C Circuit Analogy|Differential Equations

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to correctly apply Newton's laws in a rotating reference frame and linearize non-linear force fields (the gravity gradient).

The primary trap is assuming the effective restoring force is either just the spring constant kk (ignoring the rotating frame entirely) or k+mω02k + m\omega_0^2 (incorrectly applying the effective potential of a free orbit where angular momentum is conserved).

Because the payload is constrained in a radial tube, its angular velocity is forced to be constant (ω0\omega_0), meaning angular momentum is not conserved.

This leads to a centrifugal force that increases with rr and a gravity gradient that also pulls outward relative to equilibrium, creating a 'negative spring' effect of −3mω02-3m\omega_0^2 that must be subtracted from kk.

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Question Information

SubjectPhysics
ChapterGravitation - Class 11 Part 1
ConceptGeostationary Satellite Constraints
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree