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Question #43532

Difficulty: 8/10 | 🟢 Free

The Question

A uniform elastic rod of length LL, cross-sectional area AA, and Young's modulus YY is initially unstretched. One end is fixed to a rigid wall. At t=0t=0, a motorized mechanism attached to the free end begins to stretch the rod. The mechanism is programmed to deliver a transient mechanical power P(t)=P0e−t/τP(t) = P_0 e^{-t/\tau} entirely into the rod, where P0P_0 and τ\tau are positive constants. Assume the rod's mass is negligible, the process is isothermal, and all delivered work is stored as elastic potential energy. If the breaking stress of the rod's material is σb\sigma_b, at what time tbt_b will the rod break? (Assume 2YP0τ>ALσb22 Y P_0 \tau > A L \sigma_b^2).

Options

  • A.

    τln⁡(2YP0τ2YP0τ−ALσb2)\tau \ln \left( \frac{2 Y P_0 \tau}{2 Y P_0 \tau - A L \sigma_b^2} \right)

  • B.

    τln⁡(YP0τYP0τ−ALσb2)\tau \ln \left( \frac{Y P_0 \tau}{Y P_0 \tau - A L \sigma_b^2} \right)

  • C.

    τln⁡(P0τALσb)\tau \ln \left( \frac{P_0 \tau}{A L \sigma_b} \right)

  • D.

    τln⁡(2YP0τ+ALσb22YP0τ)\tau \ln \left( \frac{2 Y P_0 \tau + A L \sigma_b^2}{2 Y P_0 \tau} \right)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Stress vs. Strain Definition|Breaking Stress Concept|Transient Current Analogy

Why This Question Is Tricky

Common Mistakes

This question tests the Energy-Equivalence Principle in the context of a time-varying transient load.

A common trap is for students to erroneously attempt to extract a time-varying force F(t)F(t) from the power equation and directly equate the instantaneous stress F(t)/AF(t)/A to the breaking stress σb\sigma_b.

This ignores the fundamental principle that stress is a state variable dependent on the accumulated internal strain energy (dU=P(t)dtdU = P(t)dt), not the instantaneous external power.

By forcing students to integrate the transient power P(t)P(t) to find the accumulated work, and equating this to the elastic strain energy density U=12ALYσ2U = \frac{1}{2} \frac{AL}{Y} \sigma^2, the problem evaluates their ability to link non-conservative transient inputs (analogous to an RL circuit discharge) to conservative elastic potential energy.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMechanical Properties of Solids - Class 11 Part 2
ConceptStress vs. Strain Definition
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree