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Question #43577

Difficulty: 8/10 | 🟢 Free

The Question

A coherent point light source SS emitting light of wavelength λ\lambda (in m\text{m}) is attached to the bob of a simple pendulum. The pendulum consists of a small spherical bob of mass mm (in kg\text{kg}) and radius aa (in m\text{m}), suspended by a massless string of length LL (in m\text{m}). The source SS is positioned at a distance D′D' (in m\text{m}) behind a plane containing two narrow slits separated by a distance dd (in m\text{m}). The equilibrium position of the pendulum lies exactly on the central axis of the double-slit system. The pendulum oscillates in a vertical plane parallel to the slit plane, within a medium of viscosity η\eta (in Pa⋅s\text{Pa}\cdot\text{s}). At t=0t=0, the pendulum is released from a small initial angular displacement θ0\theta_0 (in rad\text{rad}). An interference pattern is observed on a screen placed at a distance DD (in m\text{m}) from the slits. (Assume the initial amplitude of the central maximum is strictly greater than one fringe width). Assuming small angle approximations and underdamped oscillations, what is the time tt (in s\text{s}) after which the amplitude of oscillation of the central maximum on the screen reduces to exactly one fringe width?

Options

  • A.

    m3πηaln⁡(dLθ0λD′) s\frac{m}{3\pi \eta a} \ln\left( \frac{d L \theta_0}{\lambda D'} \right) \text{ s}

  • B.

    m6πηaln⁡(dLθ0λD′) s\frac{m}{6\pi \eta a} \ln\left( \frac{d L \theta_0}{\lambda D'} \right) \text{ s}

  • C.

    m3πηaln⁡(dLθ0λD) s\frac{m}{3\pi \eta a} \ln\left( \frac{d L \theta_0}{\lambda D} \right) \text{ s}

  • D.

    m3πηaln⁡(dDLθ0λD′2) s\frac{m}{3\pi \eta a} \ln\left( \frac{d D L \theta_0}{\lambda D'^2} \right) \text{ s}

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Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Optical Path Difference|Simple Pendulum Small Angle Approximation|Oscillations

Why This Question Is Tricky

Common Mistakes

This question tests the synthesis of wave optics and damped rotational kinematics.

The primary trap lies in the misapplication of the small angle approximation and the damping coefficient.

Students often incorrectly assume the central maximum shift is equal to the source displacement, forgetting the magnification factor D/D′D/D' derived from the optical path difference equation.

Furthermore, when applying Newton's Second Law for Rotation, a common error is writing the viscous drag torque as −bθ˙-b\dot{\theta} instead of −bL2θ˙-bL^2\dot{\theta} (since v=Lθ˙v = L\dot{\theta}), or forgetting the factor of 2 in the standard differential equation θ¨+2γθ˙+ω02θ=0\ddot{\theta} + 2\gamma\dot{\theta} + \omega_0^2\theta = 0.

This leads to an incorrect damping factor γ\gamma, trapping them in options with incorrect prefactors.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWave Optics - Class 12
ConceptOptical Path Difference
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree