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Question #43612

Difficulty: 8/10 | 🟢 Free

The Question

Two broad, coherent monochromatic light beams, each of wavelength λ\lambda and uniform intensity I0I_0 (defined as power per unit area perpendicular to the direction of propagation), are incident on a flat photosensitive plate lying in the x−yx-y plane. The wave vectors of the two beams lie in the x−zx-z plane and make angles of +θ+\theta and −θ-\theta with the zz-axis (which is normal to the plate). The beams are polarized with their electric fields parallel to the yy-axis, and are in phase at the origin (0,0,0)(0,0,0). A rectangular photosensitive strip of width ww (along the yy-axis) and length L=λ6sin⁡θL = \frac{\lambda}{6 \sin\theta} (along the xx-axis) is marked on the plate from x=0x=0 to x=Lx=L. The work function of the strip is ϕ\phi (where ϕ<hc/λ\phi < hc/\lambda), and its quantum efficiency is η\eta (number of photoelectrons emitted per incident photon). Assuming all emitted photoelectrons are collected, what is the total photoelectric current ii generated by the strip? (Here ee is the elementary charge, hh is Planck's constant, and cc is the speed of light)

Options

  • A.

    eηI0λ2wcot⁡θhc(13+34π)\frac{e \eta I_0 \lambda^2 w \cot\theta}{hc} \left( \frac{1}{3} + \frac{\sqrt{3}}{4\pi} \right)

  • B.

    eηI0λ2wcot⁡θhc(13−34π)\frac{e \eta I_0 \lambda^2 w \cot\theta}{hc} \left( \frac{1}{3} - \frac{\sqrt{3}}{4\pi} \right)

  • C.

    eηI0λ2wcot⁡θ3hc\frac{e \eta I_0 \lambda^2 w \cot\theta}{3hc}

  • D.

    eηI0λ2wcsc⁡θ3hc\frac{e \eta I_0 \lambda^2 w \csc\theta}{3hc}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Einstein's Photoelectric Equation|Superposition Principle|Phase Relationship|Vector Cross-Products

Why This Question Is Tricky

Common Mistakes

This question tests the synthesis of wave optics (interference) and modern physics (photoelectric effect).

The primary trap is assuming the total intensity on the plate is simply the sum of the individual intensities (2I02I_0 or 2I0cos⁡θ2I_0\cos\theta), ignoring the spatial variation caused by the superposition of the coherent beams.

A secondary trap is forgetting the geometric projection factor (cos⁡θ\cos\theta) when converting the beam's cross-sectional intensity to the intensity on the flat plate.

Students must recognize that photoelectric current is proportional to the localized photon flux, requiring an exact integration of the interference pattern over the specific dimensions of the strip.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterDual Nature of Radiation and Matter - Class 12
ConceptEinstein's Photoelectric Equation
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree