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Question #43644

Difficulty: 8/10 | 🟢 Free

The Question

Consider a hypothetical hydrogen-like atom where the nucleus is not a point charge, but a non-conducting solid sphere of radius RR. The volume charge density of the nucleus is given by ρ(r)=ρ0(rR)\rho(r) = \rho_0 \left(\frac{r}{R}\right) for r≤Rr \le R, where ρ0\rho_0 is a positive constant and rr is the radial distance from the center. The total charge of the nucleus is +e+e. An electron of mass mm and charge −e-e revolves around the center of the nucleus in a circular Bohr orbit. Assuming the nthn^{\text{th}} Bohr orbit lies entirely inside the nucleus (rn<Rr_n < R), which of the following expressions represents the radius rnr_n of this orbit? (Here ϵ0\epsilon_0 is the permittivity of free space and ℏ=h2π\hbar = \frac{h}{2\pi} is the reduced Planck constant).

Options

  • A.

    (4πϵ0R4n2ℏ2me2)15\left( \frac{4\pi \epsilon_0 R^4 n^2 \hbar^2}{m e^2} \right)^{\frac{1}{5}}

  • B.

    (4πϵ0R2n2ℏ2me2)13\left( \frac{4\pi \epsilon_0 R^2 n^2 \hbar^2}{m e^2} \right)^{\frac{1}{3}}

  • C.

    (4πϵ0R3n2ℏ2me2)14\left( \frac{4\pi \epsilon_0 R^3 n^2 \hbar^2}{m e^2} \right)^{\frac{1}{4}}

  • D.

    (2πϵ0R4n2ℏ2me2)15\left( \frac{2\pi \epsilon_0 R^4 n^2 \hbar^2}{m e^2} \right)^{\frac{1}{5}}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Coulombic Central Force|Principle of Superposition|Non-conducting Charged Sphere|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to synthesize electrostatics (Gauss's Law for non-uniform continuous charge distributions) with modern physics (Bohr model).

The primary trap lies in the assumption of the effective central force.

Students often blindly apply the standard inverse-square Coulomb force (F∝1/r2F \propto 1/r^2) or assume a uniform charge density (F∝rF \propto r) inside the nucleus.

By introducing a linearly varying charge density ρ(r)∝r\rho(r) \propto r, the enclosed charge scales as r4r^4, leading to an electric field that scales as r2r^2.

This fundamentally alters the centripetal force balance and the resulting dependence of the orbital radius on the principal quantum number nn.

Furthermore, the options are carefully constructed to be dimensionally identical, neutralizing dimensional analysis as a guessing strategy and forcing rigorous integration of the spherical volume element 4πr2dr4\pi r^2 dr.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterAtoms - Class 12
ConceptCoulombic Central Force
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree