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Question #43652
The Question
A hypothetical 'gravitational atom' consists of a particle of mass orbiting a central star of mass () under purely gravitational forces. The system's energy levels are quantized according to Bohr's postulates. Let be the magnitude of the initial ground state energy of this system. The central star slowly and isotropically loses mass due to radiation over a very long time, until its mass becomes . The process is slow enough that the orbital quantum number remains an adiabatic invariant. Assuming the emitted radiation does not interact with the orbiting particle, find the new ground state binding energy and the work done by the gravitational force on the particle during this entire process.
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Variable_Constraint
Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.
Concepts Behind This Question
Rydberg Constant Sensitivity|Orbital Velocity Energy Balance|Integration
Why This Question Is Tricky
Common Mistakes
This question tests the limits of the work-energy theorem and the concept of adiabatic invariants in a Bohr-quantized system.
The primary trap is the misapplication of potential energy in a time-varying field.
Students commonly assume that the work done by gravity is or .
However, because the central mass is decreasing, the gravitational potential field is explicitly time-dependent.
In such fields, the standard relation fails because the potential energy changes even when the particle is stationary.
The rigorous approach relies on the fundamental work-energy theorem for a single particle, .
Furthermore, students must correctly derive that the energy levels of a gravitational Bohr atom scale with , not , to find the correct final state.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Atoms - Class 12 |
| Concept | Rydberg Constant Sensitivity |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |