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Question #43653
The Question
A spherical blackbody of radius is maintained at a temperature such that , where is the Rydberg constant. It is surrounded by a thin, optically thick shell of hydrogen gas in its ground state. The shell absorbs all incident photons from the blackbody that have an energy greater than or equal to the ionization energy of hydrogen. Assume that each absorbed ionizing photon causes exactly one ionization event, and the subsequent recombination cascade produces exactly one Lyman- photon (transition from to ).
Using Wien's approximation for the spectral emissive power (power emitted per unit area per unit wavelength) , determine the total power emitted by the hydrogen shell in the Lyman- line.
(Assume for , where and corresponds to the ionization threshold).
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Rydberg Constant Sensitivity|Stefan-Boltzmann Power Law|Intensity and Photon Flux
Why This Question Is Tricky
Common Mistakes
This question tests the critical distinction between energy flux and photon flux in quantum emission processes.
Students often fall into the trap of applying energy conservation directly—integrating the total energy of the continuous ionizing spectrum and equating it to the energy emitted in the discrete Lyman-alpha line.
However, in this recombination cascade model, it is the number of photons (ionization events) that is conserved, not the energy.
The excess energy of the absorbed photons thermalizes the gas, while only a fixed quantum (3/4 hc R_H) is radiated per event.
Integrating the energy flux yields the incorrect coefficient of 8π², whereas correctly integrating the photon flux yields 6π².
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Atoms - Class 12 |
| Concept | Rydberg Constant Sensitivity |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |