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Question #43659

Difficulty: 8/10 | 🟢 Free

The Question

A particle of mass MM is moving in a horizontal plane along a circular path of radius RR with constant angular speed ω\omega, constrained by a massless radial string. At a certain instant, the string snaps and simultaneously the particle ejects a fragment of mass mm tangentially forward. In the reference frame moving with the instantaneous velocity of the particle just before ejection, the ejected fragment has a speed uu in the forward direction. What is the kinetic energy of the remaining fragment in the laboratory frame immediately after the ejection?

Options

  • A.

    12(M−m)ω2R2−muωR+m2u22(M−m)\frac{1}{2} (M-m) \omega^2 R^2 - m u \omega R + \frac{m^2 u^2}{2(M-m)}

  • B.

    12(M−m)ω2R2+muωR+m2u22(M−m)\frac{1}{2} (M-m) \omega^2 R^2 + m u \omega R + \frac{m^2 u^2}{2(M-m)}

  • C.

    12(M−m)ω2R2+m2u22(M−m)\frac{1}{2} (M-m) \omega^2 R^2 + \frac{m^2 u^2}{2(M-m)}

  • D.

    12Mω2R2+m2u22(M−m)\frac{1}{2} M \omega^2 R^2 + \frac{m^2 u^2}{2(M-m)}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Recoil of Atom|Relative Velocity in 2D|Vector Cross-Products

Why This Question Is Tricky

Common Mistakes

This question tests the critical distinction between vector momentum conservation and scalar energy adjustments in non-zero momentum frames.

A common lethal trap for JEE Advanced students is calculating the recoil energy in the center-of-mass frame (Erecoil=m2u22(M−m)E_{recoil} = \frac{m^2 u^2}{2(M-m)}) and erroneously adding it directly to the base kinetic energy of the remaining mass (Option C).

This scalar approach completely ignores the Galilean transformation of kinetic energy, specifically the cross-term (−muωR-mu\omega R) that arises from the dot product of the initial velocity vector and the recoil velocity vector.

By forcing the emission to be tangential, the cross-term is maximized, heavily penalizing students who bypass strict vector momentum conservation.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterAtoms - Class 12
ConceptRecoil of Atom
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree