Before You Begin
Question #43659
The Question
A particle of mass is moving in a horizontal plane along a circular path of radius with constant angular speed , constrained by a massless radial string. At a certain instant, the string snaps and simultaneously the particle ejects a fragment of mass tangentially forward. In the reference frame moving with the instantaneous velocity of the particle just before ejection, the ejected fragment has a speed in the forward direction. What is the kinetic energy of the remaining fragment in the laboratory frame immediately after the ejection?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Recoil of Atom|Relative Velocity in 2D|Vector Cross-Products
Why This Question Is Tricky
Common Mistakes
This question tests the critical distinction between vector momentum conservation and scalar energy adjustments in non-zero momentum frames.
A common lethal trap for JEE Advanced students is calculating the recoil energy in the center-of-mass frame () and erroneously adding it directly to the base kinetic energy of the remaining mass (Option C).
This scalar approach completely ignores the Galilean transformation of kinetic energy, specifically the cross-term () that arises from the dot product of the initial velocity vector and the recoil velocity vector.
By forcing the emission to be tangential, the cross-term is maximized, heavily penalizing students who bypass strict vector momentum conservation.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Atoms - Class 12 |
| Concept | Recoil of Atom |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |