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Question #43695

Difficulty: 8/10 | 🟢 Free

The Question

A toroidal coil of rectangular cross-section has an inner radius aa, outer radius bb, height hh, and a total of NN turns. A thin, straight capillary tube passes exactly along the axis of symmetry of the toroid. The tube contains a sample of a radioactive isotope that undergoes alpha decay, emitting α\alpha particles (each with charge +2e+2e). At time t=0t=0, the number of radioactive nuclei is N0N_0, and the decay constant of the isotope is λ\lambda. An external mechanism ensures that all emitted α\alpha particles are immediately swept along the tube in the same direction, forming a continuous narrow beam. Assume the transit time of the particles through the toroid is negligible, so the beam acts as a long straight wire carrying a spatially uniform, time-varying current. What is the magnitude of the maximum induced electromotive force (EMF) in the toroidal coil? (Assume all quantities are in SI units and μ0\mu_0 is the permeability of free space)

Options

  • A.

    μ0Nheλ2N0πln⁡(ba)\frac{\mu_0 N h e \lambda^2 N_0}{\pi} \ln\left(\frac{b}{a}\right)

  • B.

    μ0NheλN0πln⁡(ba)\frac{\mu_0 N h e \lambda N_0}{\pi} \ln\left(\frac{b}{a}\right)

  • C.

    μ0Nhλ2N02πln⁡(ba)\frac{\mu_0 N h \lambda^2 N_0}{2\pi} \ln\left(\frac{b}{a}\right)

  • D.

    μ0NhλN02πln⁡(ba)\frac{\mu_0 N h \lambda N_0}{2\pi} \ln\left(\frac{b}{a}\right)

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Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Statistical Nature of Decay|Mutual Inductance Reciprocity|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the synthesis of statistical radioactive decay and electromagnetic induction, specifically targeting the misconception of treating decay rate directly as an EMF surrogate.

Students often correctly identify that current is proportional to the decay rate (I∝dN/dt∝λe−λtI \propto dN/dt \propto \lambda e^{-\lambda t}), but fail to apply Faraday's Law correctly, which requires the time derivative of the magnetic flux (E=−dΦ/dt\mathcal{E} = -d\Phi/dt).

Consequently, the induced EMF depends on the second derivative of the nuclei count (d2N/dt2d^2N/dt^2), introducing an additional factor of λ\lambda.

Furthermore, the trap punishes students who conflate 'decay events per unit time' with 'charge per unit time' by omitting the specific charge of the α\alpha particle (+2e+2e).

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterNuclei - Class 12
ConceptStatistical Nature of Decay
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree