Start Learning Free

Before You Begin

Question #43716

Difficulty: 8/10 | 🟢 Free

The Question

Consider an intrinsic semiconductor at room temperature with an intrinsic carrier concentration ni=3.0×1010 cm−3n_i = 3.0 \times 10^{10} \text{ cm}^{-3}. The recombination of electrons and holes is a bimolecular process, meaning the recombination rate per unit volume is given by R=βnpR = \beta n p, where nn and pp are the electron and hole concentrations, respectively, and β=1.0×10−10 cm3s−1\beta = 1.0 \times 10^{-10} \text{ cm}^3 \text{s}^{-1} is the recombination coefficient. In thermal equilibrium, the thermal generation rate GthG_{th} balances the recombination rate. The semiconductor is now continuously illuminated, providing an additional, steady external generation rate of electron-hole pairs Gext=1.6×1011 cm−3s−1G_{ext} = 1.6 \times 10^{11} \text{ cm}^{-3} \text{s}^{-1}. Assuming uniform illumination and no spatial gradients, what is the steady-state excess electron concentration Δn\Delta n in the semiconductor?

Options

  • A.

    1.0×1010 cm−31.0 \times 10^{10} \text{ cm}^{-3}

  • B.

    2.0×1010 cm−32.0 \times 10^{10} \text{ cm}^{-3}

  • C.

    4.0×1010 cm−34.0 \times 10^{10} \text{ cm}^{-3}

  • D.

    5.0×1010 cm−35.0 \times 10^{10} \text{ cm}^{-3}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Law of Mass Action|Successive Decay Equilibrium|First-Order Kinetics

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to model steady-state equilibrium in a system with nonlinear (bimolecular) recombination kinetics, drawing a mathematical analogy to radioactive secular equilibrium.

The primary trap lies in misapplying the principle of superposition to nonlinear rates.

Students often incorrectly assume that the external generation rate only balances the excess recombination rate via Gext=βΔn2G_{ext} = \beta \Delta n^2 (yielding Option C), or they ignore the continuous thermal generation background GthG_{th} entirely, setting Gext=βn2G_{ext} = \beta n^2 (yielding Option A).

The correct approach requires recognizing that the total generation rate (Gth+GextG_{th} + G_{ext}) must balance the total nonlinear recombination rate (βn2\beta n^2), preventing the separation of equilibrium and excess components into independent linear equations.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterSemiconductor Electronics: Materials, Devices, and Simple Circuits - Class 12
ConceptLaw of Mass Action
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree