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Question #43759

Difficulty: 8/10 | 🟢 Free

The Question

A solid non-conducting sphere of uniform charge QQ (Coulombs), initial radius RR (meters), and bare mechanical mass mm (kg) is moving with a constant non-relativistic velocity v0v_0 (m/s) along the x-axis in a field-free vacuum. An internal mechanism causes the sphere to slowly expand radially to a new radius 2R2R while maintaining a uniform charge distribution. Assume no external forces act on the system and radiation losses are negligible. Let cc (m/s) be the speed of light in vacuum and ϵ0\epsilon_0 (F/m) be the vacuum permittivity. If the total momentum of the system is given by P⃗=mv⃗+p⃗em\vec{P} = m\vec{v} + \vec{p}_{em}, where p⃗em=ϵ0∫(E⃗×B⃗)dV\vec{p}_{em} = \epsilon_0 \int (\vec{E} \times \vec{B}) dV is the electromagnetic field momentum (with E⃗\vec{E} and B⃗\vec{B} being the fields generated by the sphere), what is the final velocity vfv_f of the sphere?

Options

  • A.

    v0v_0

  • B.

    v0(m+3Q220πϵ0Rc2m+3Q240πϵ0Rc2)v_0 \left( \frac{m + \frac{3Q^2}{20\pi\epsilon_0 R c^2}}{m + \frac{3Q^2}{40\pi\epsilon_0 R c^2}} \right)

  • C.

    v0(m+Q25πϵ0Rc2m+Q210πϵ0Rc2)v_0 \left( \frac{m + \frac{Q^2}{5\pi\epsilon_0 R c^2}}{m + \frac{Q^2}{10\pi\epsilon_0 R c^2}} \right)

  • D.

    v0(m+Q26πϵ0Rc2m+Q212πϵ0Rc2)v_0 \left( \frac{m + \frac{Q^2}{6\pi\epsilon_0 R c^2}}{m + \frac{Q^2}{12\pi\epsilon_0 R c^2}} \right)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Instantaneous Nature|Energy Density Locality|Non-conducting Charged Sphere

Why This Question Is Tricky

Common Mistakes

This question tests the concept of electromagnetic field momentum and its role in the conservation of total momentum.

A common trap is the 'Self-Energy Paradox' where students either completely ignore the momentum carried by the electromagnetic field (Option A) or incorrectly assume the electromagnetic mass is simply Ue/c2U_e/c^2 (Option B).

By explicitly requiring the evaluation of p⃗em=ϵ0∫(E⃗×B⃗)dV\vec{p}_{em} = \epsilon_0 \int (\vec{E} \times \vec{B}) dV, the problem forces students to derive the subtle 4/34/3 factor (p⃗em=43c2Uev⃗\vec{p}_{em} = \frac{4}{3c^2}U_e \vec{v}) inherent to the classical electron model.

Furthermore, Option D traps students who carelessly use the self-energy of a spherical shell instead of a solid sphere.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterDual Nature of Radiation and Matter - Class 12
ConceptInstantaneous Nature
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree