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Question #43761

Difficulty: 8/10 | 🟢 Free

The Question

In a modified Young's Double Slit Experiment, a primary source placed symmetrically with respect to two narrow slits S1S_1 and S2S_2 emits a single, ultra-short light pulse of duration τ\tau. The pulse has a rectangular time envelope, meaning its intensity is constant for a duration τ\tau and zero otherwise. The slits are separated by a distance dd, and the screen is placed at a distance DD (D≫dD \gg d). The intensity of the pulse arriving from each slit individually at the screen is I0I_0.

A detector at a point PP on the screen, located at a distance yy from the central maximum, measures the total time-integrated energy per unit area (fluence, FF). If yy is such that the path difference Δx=ydD\Delta x = \frac{yd}{D} satisfies 0<Δx<cτ0 < \Delta x < c\tau (where cc is the speed of light in vacuum), which of the following expressions correctly represents the fluence FF at point PP?

(Assume the phase difference between the waves during their overlap is Δϕ=2πydλD\Delta \phi = \frac{2\pi yd}{\lambda D}, where λ\lambda is the wavelength of the light).

Options

  • A.

    2I0τ[1+(1−ydcτD)cos⁡(2πydλD)]2I_0 \tau \left[ 1 + \left(1 - \frac{yd}{c\tau D}\right) \cos\left(\frac{2\pi yd}{\lambda D}\right) \right]

  • B.

    2I0τ[1+cos⁡(2πydλD)]2I_0 \tau \left[ 1 + \cos\left(\frac{2\pi yd}{\lambda D}\right) \right]

  • C.

    2I0(τ−ydcD)[1+cos⁡(2πydλD)]2I_0 \left(\tau - \frac{yd}{cD}\right) \left[ 1 + \cos\left(\frac{2\pi yd}{\lambda D}\right) \right]

  • D.

    2I0τ[1+(ydcτD)cos⁡(2πydλD)]2I_0 \tau \left[ 1 + \left(\frac{yd}{c\tau D}\right) \cos\left(\frac{2\pi yd}{\lambda D}\right) \right]

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Instantaneous Nature|Young's Double Slit Geometry|Optical Path Difference

Why This Question Is Tricky

Common Mistakes

This question tests the student's understanding of the instantaneous nature of wave interference and coherence time.

The standard trap (Option B) assumes that the time-integrated intensity of a pulse is simply the continuous-wave interference pattern multiplied by the pulse duration.

Students falling into this trap fail to recognize that wave packets of finite spatial length cτc\tau only partially overlap at the screen if there is a path difference.

Another lethal trap (Option C) correctly identifies the reduced overlap time but completely ignores the energy deposited by the non-overlapping tails of the wave packets.

The correct framework requires integrating the instantaneous intensity over time, explicitly separating the coherent overlap phase from the incoherent single-pulse phases.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterDual Nature of Radiation and Matter - Class 12
ConceptInstantaneous Nature
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree