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Question #43810

Difficulty: 8/10 | 🟢 Free

The Question

According to the Liquid Drop Model, a heavy nucleus of mass number AA and atomic number ZZ can be modeled as a spherical drop of incompressible nuclear fluid of radius R=R0A1/3R = R_0 A^{1/3}. The strong nuclear force creates an effective surface tension γ\gamma and an internal pressure PintP_{\text{int}} to maintain mechanical equilibrium. The protons are assumed to be uniformly distributed throughout the nuclear volume, creating an electrostatic Coulomb energy Ec=35(Ze)24πϵ0RE_c = \frac{3}{5} \frac{(Ze)^2}{4\pi \epsilon_0 R}. Which of the following expressions gives the correct internal pressure PintP_{\text{int}} required to maintain mechanical equilibrium of the nucleus?

Options

  • A.

    2γR0A1/3−3Z2e280π2ϵ0R04A4/3\frac{2\gamma}{R_0 A^{1/3}} - \frac{3 Z^2 e^2}{80 \pi^2 \epsilon_0 R_0^4 A^{4/3}}

  • B.

    2γR0A1/3+3Z2e280π2ϵ0R04A4/3\frac{2\gamma}{R_0 A^{1/3}} + \frac{3 Z^2 e^2}{80 \pi^2 \epsilon_0 R_0^4 A^{4/3}}

  • C.

    2γR0A1/3−9Z2e280π2ϵ0R04A4/3\frac{2\gamma}{R_0 A^{1/3}} - \frac{9 Z^2 e^2}{80 \pi^2 \epsilon_0 R_0^4 A^{4/3}}

  • D.

    2γR0A1/3\frac{2\gamma}{R_0 A^{1/3}}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Nuclear Radius Scaling|Excess Pressure (Laplace Law)|Approximations

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to adapt macroscopic thermodynamic and fluid mechanics concepts (Laplace pressure) to a quantum/nuclear system (Liquid Drop Model).

The primary trap is blindly applying the standard Laplace excess pressure formula (ΔP=2γ/R\Delta P = 2\gamma/R) without accounting for the outward 'negative pressure' exerted by the Coulomb repulsion of the protons.

A secondary trap involves incorrectly calculating the Coulomb pressure by simply dividing the Coulomb energy by the volume (Ec/VE_c/V) rather than taking the proper thermodynamic volume derivative (−∂Ec/∂V-\partial E_c/\partial V).

This highlights the misconception between energy density and thermodynamic pressure in systems with non-linear volume dependencies.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterNuclei - Class 12
ConceptNuclear Radius Scaling
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree