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Question #43970

Difficulty: 8/10 | 🟢 Free

The Question

An organic compound \textbf{X} (\ceC10H10O2\ce{C10H10O2}) gives a positive Tollens' test and a positive iodoform test. A student attempts to perform a Cannizzaro reaction on \textbf{X} by treating it with 50% aqueous \ceNaOH\ce{NaOH} at 100∘C100^\circ\text{C}, assuming the aldehyde group lacks α\alpha-hydrogens. However, the reaction yields a single major aromatic product \textbf{Y} (\ceC10H8O\ce{C10H8O}) instead of the expected disproportionation products. Which of the following represents the correct structure of \textbf{Y}?

Options

  • A.

    Naphthalen-2-ol

  • B.

    Naphthalen-1-ol

  • C.

    Equimolar mixture of 2-(2-oxopropyl)benzoic acid and 2-(2-oxopropyl)benzyl alcohol

  • D.

    3-Methyl-1H-inden-1-ol

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Cannizzaro Mechanism|Alpha-Hydrogen Acidity|Aldol Condensation Directionality

Why This Question Is Tricky

Common Mistakes

This problem tests the competition between the Cannizzaro reaction and the Aldol condensation.

Students often blindly apply the heuristic 'no alpha-hydrogens on the aldehyde = Cannizzaro'.

The trap involves a 'hidden' acidic proton on a remote substituent (the methyl ketone) that shifts the reaction pathway entirely.

The formation of a resonance-stabilized enolate outcompetes the intermolecular hydroxide attack required for Cannizzaro, leading to an intramolecular cyclization and subsequent aromatization.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterAldehydes, Ketones, and Carboxylic Acids - Class 12
ConceptCannizzaro Mechanism
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree