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Question #43998
The Question
Consider the following carbohydrate derivatives: \begin{itemize} \item \textbf{X}: 1-O-acetyl--D-glucopyranose \item \textbf{Y}: Methyl -D-glucopyranoside \item \textbf{Z}: 2-O-methyl-D-glucose \end{itemize} Each compound is independently heated with an excess of phenylhydrazine in an aqueous acetate buffer (pH ) at . Which of the following correctly describes the major outcome for each compound?
Options
- A.
\textbf{X} yields D-glucosazone; \textbf{Y} remains unreacted; \textbf{Z} yields a monophenylhydrazone.
- B.
\textbf{X} and \textbf{Y} remain unreacted; \textbf{Z} yields D-glucosazone.
- C.
\textbf{X} yields a monophenylhydrazone; \textbf{Y} yields D-glucosazone; \textbf{Z} remains unreacted.
- D.
All three compounds yield D-glucosazone due to the acidic hydrolysis of their respective protecting groups.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Esterification Reversibility|Reducing Sugar Criteria|Osazone Formation Logic
Why This Question Is Tricky
Common Mistakes
The question tests the dynamic nature of 'reducing sugar' criteria and the mechanistic requirements for osazone formation.
The primary trap is assuming that 1-O-acetyl-beta-D-glucopyranose (X) is permanently non-reducing because its anomeric center is protected.
Students overlook that anomeric esters are susceptible to nucleophilic acyl substitution (aminolysis) by phenylhydrazine, which unmasks the free sugar in situ.
A secondary trap is assuming that 2-O-methyl-D-glucose (Z) can form an osazone, failing to recognize that the C2 hydroxyl must be free for the Amadori-type rearrangement to proceed.
Finally, distinguishing the stability of an ester (X) versus an acetal (Y) under mildly acidic/nucleophilic conditions is a classic test of functional group reactivity.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Aldehydes, Ketones, and Carboxylic Acids - Class 12 |
| Concept | Esterification Reversibility |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |