Question #44027

Consider the exhaustive ammonolysis of methyl iodide (\ce{CH3I}) and ethyl iodide (\ce{C2H5I}) in separate reaction vessels, followed by the isolation of the respective primary ($1^\circ$), secondary ($2^\circ$), and tertiary ($3^\circ$) amines.

Let $A_{max}$ and $A_{min}$ be the most basic and least basic amines (among the $1^\circ, 2^\circ$, and $3^\circ$ amines) derived from \ce{CH3I} in aqueous solution at 298 K. Let $B_{max}$ and $B_{min}$ be the most basic and least basic amines (among the $1^\circ, 2^\circ$, and $3^\circ$ amines) derived from \ce{C2H5I} in aqueous solution at 298 K.

Calculate the value of $(x + y)$, where $x$ is the total number of $\alpha$-hydrogens in $A_{max}$ and $A_{min}$, and $y$ is the total number of $\alpha$-hydrogens in $B_{max}$ and $B_{min}$.

(Note: $\alpha$-hydrogens are the hydrogen atoms attached to the carbon atoms directly bonded to the nitrogen atom).