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Question #44030

Difficulty: 8/10 | 🟢 Free

The Question

Aniline undergoes electrophilic aromatic substitution with a nitrating mixture (conc. \ce{HNO3} and conc. \ce{H2SO4}) at 288 K288\text{ K} to form three mononitrated products PP, QQ, and RR with yields of 51%51\%, 47%47\%, and 2%2\% respectively. Product QQ is isolated and treated with \ce{NaNO2}/\ce{HCl} at 273−278 K273-278\text{ K}, followed by reaction with \ce{H3PO2} and \ce{H2O} to yield compound XX. In a parallel experiment, aniline is first treated with acetic anhydride in the presence of pyridine, then nitrated using the same nitrating mixture at 288 K288\text{ K}, and finally hydrolyzed with dilute \ce{H2SO4} to give compound SS as the major product. SS is then subjected to diazotization (\ce{NaNO2}/\ce{HCl} at 273−278 K273-278\text{ K}) followed by a Sandmeyer reaction with \ce{CuCN}/\ce{KCN} and subsequent complete acidic hydrolysis to yield compound YY. Identify compounds XX and YY.

Options

  • A.

    X=X = Nitrobenzene, Y=Y = 4-Nitrobenzoic acid

  • B.

    X=X = 3-Nitrophenol, Y=Y = 4-Nitrobenzoic acid

  • C.

    X=X = Nitrobenzene, Y=Y = 4-Aminobenzoic acid

  • D.

    X=X = 1,3-Dinitrobenzene, Y=Y = 4-Nitrobenzamide

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Aniline Resonance Pitfalls|Ortho-Effect in Anilines|Electrophilic Substitution Control

Why This Question Is Tricky

Common Mistakes

This problem tests the 'Acidic Medium Trap' in aniline electrophilic substitution.

Students often assume the \ce{-NH2} group remains strongly activating and ortho/para directing, ignoring its protonation to the meta-directing \ce{-NH3+} ion in a nitrating mixture, which produces an anomalous 47%47\% yield of m-nitroaniline.

It also evaluates the strategic use of protecting groups (acetylation) to restore ortho/para regioselectivity and prevent oxidation.

Finally, it tests the specific reactivity of diazonium salts, specifically the reductive deamination by \ce{H3PO2} versus cyanation and subsequent complete hydrolysis of nitriles to carboxylic acids.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterAmines - Class 12
ConceptAniline Resonance Pitfalls
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree