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Question #44041

Difficulty: 8/10 | 🟢 Free

The Question

A primary alkyl halide XX (\ceC5H11Br\ce{C5H11Br}) is treated with potassium phthalimide in N,NN,N-dimethylformamide (DMF) at 353 K353\text{ K}. The reaction fails to yield the expected NN-alkylphthalimide. However, when XX is heated with aqueous \ceAgNO3\ce{AgNO3}, it forms a pale yellow precipitate and yields an alcohol YY. Alcohol YY produces immediate turbidity upon treatment with Lucas reagent (\ceZnCl2\ce{ZnCl2} / conc. \ceHCl\ce{HCl}). Identify XX and the primary kinetic barrier preventing its reaction with potassium phthalimide.

Options

  • A.

    1-Bromo-2,2-dimethylpropane; Severe steric hindrance at the β\beta-carbon prevents the required SN2S_N2 backside attack.

  • B.

    1-Bromo-2-methylbutane; The phthalimide anion acts as a strong base, leading to an E2E2 elimination pathway.

  • C.

    1-Bromo-2,2-dimethylpropane; The highly stable neopentyl carbocation intermediate favors an SN1S_N1 pathway, bypassing the Gabriel synthesis.

  • D.

    2-Bromo-2-methylbutane; Steric hindrance at the α\alpha-carbon blocks the SN2S_N2 trajectory of the phthalimide nucleophile.

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Gabriel Phthalimide Synthesis|Nucleophilic Acyl Substitution

Why This Question Is Tricky

Common Mistakes

This problem tests the 'Neopentyl Exception' in SN2S_N2 reactions.

Students often memorize the heuristic that 'primary alkyl halides undergo Gabriel phthalimide synthesis' and fail to account for steric hindrance at the β\beta-carbon.

By selecting neopentyl bromide, the question forces the student to recognize that the SN2S_N2 transition state requires a backside attack that is kinetically prohibited by the massive steric bulk of the adjacent \textit{tert}-butyl group.

The secondary trap (Option C) tests the misconception that neopentyl systems form stable primary carbocations, whereas they actually undergo rapid rearrangement, and Option D traps students who ignore the 'primary alkyl halide' constraint.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterAmines - Class 12
ConceptGabriel Phthalimide Synthesis
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree