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Question #44060

Difficulty: 8/10 | 🟢 Free

The Question

An aqueous solution of a weak electrolyte \ce{X} (molar mass = 120 g mol−1120 \text{ g mol}^{-1}) has an initial concentration of 2.5 M2.5 \text{ M} and a density of 1.10 g mL−11.10 \text{ g mL}^{-1} at 298 K298 \text{ K}. The electrolyte dissociates reversibly as: \ceX(aq)<=>Y(aq)+Z(aq)\ce{X(aq) <=> Y(aq) + Z(aq)} The forward reaction rate depends only on [\ceX][\ce{X}], and the backward reaction rate depends symmetrically on [\ceY][\ce{Y}] and [\ceZ][\ce{Z}]. The rate constants are given as kf=0.64 L mol−1s−1k_f = 0.64 \text{ L mol}^{-1} \text{s}^{-1} and kb=0.01 L3mol−3s−1k_b = 0.01 \text{ L}^3 \text{mol}^{-3} \text{s}^{-1}.

Assuming \ce{Y} and \ce{Z} do not undergo any further reactions and the density of the solution remains constant, calculate the depression in freezing point (ΔTf\Delta T_f) of the solution at equilibrium. (Given: KfK_f for water = 1.86 K kg mol−11.86 \text{ K kg mol}^{-1})

Options

  • A.

    10.46 K10.46 \text{ K}

  • B.

    8.37 K8.37 \text{ K}

  • C.

    10.28 K10.28 \text{ K}

  • D.

    11.41 K11.41 \text{ K}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Numerical_Precision

Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.

Concepts Behind This Question

Reaction Quotient vs. Equilibrium Constant|Degree of Dissociation/Association|Units of Rate Constant (k)

Why This Question Is Tricky

Common Mistakes

The problem tests the student's ability to link chemical kinetics with thermodynamics and colligative properties.

The 'hidden variable' is the order of the reaction, which must be deduced from the units of the rate constants.

Students often blindly use K=kf/kbK = k_f / k_b without checking the rate laws, leading to an incorrect equilibrium expression (Trap 1).

Furthermore, the problem requires calculating the freezing point depression, a colligative property that depends strictly on molality, not molarity.

Because the solution is highly concentrated, the mass of the solute is significant, making the mass of the solvent substantially less than the mass of the solution.

Students who use molarity directly in the ΔTf\Delta T_f formula will fall into Trap 2.

Finally, assuming KcK_c and KmK_m are numerically equal leads to Trap 3.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterEquilibrium - Class 11 Part 1
ConceptReaction Quotient vs. Equilibrium Constant
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree