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Question #44121
The Question
An aqueous solution of a yellow transition metal oxoanion is acidified with dilute at , yielding an orange oxoanion . Both and are diamagnetic and exhibit intense color due to Ligand-to-Metal Charge Transfer (LMCT). Let and be the oxidation states of the central metal in and respectively, as represented in their IUPAC Stock notations. Which of the following correctly identifies the Stock notations and the fundamental nature of the transformation?
Options
- A.
(VI), (VI); Non-redox condensation
- B.
(VI), (VII); Disproportionation
- C.
(IV), (VI); Oxidation
- D.
(VI), (III); Reduction
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Mechanism_Trap
Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.
Concepts Behind This Question
Stock Notation Logic|Dichromate-Chromate Equilibrium
Why This Question Is Tricky
Common Mistakes
The question tests the 'Chemical Exception' where a dramatic color change (yellow to orange) in transition metal complexes is incorrectly assumed to be a redox reaction involving a change in oxidation state.
Students frequently fall into the trap of modifying the Stock notation during the chromate-dichromate shift.
However, the equilibrium () is purely a pH-dependent condensation.
The oxidation state of Chromium remains +6 (Stock notation VI) in both the tetrahedral chromate and the bridged dichromate.
The intense colors arise from Ligand-to-Metal Charge Transfer (LMCT) in the metal centers, not from d-d transitions or redox processes.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Redox Reactions - Class 11 Part 2 |
| Concept | Stock Notation Logic |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |