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Question #44147

Difficulty: 8/10 | 🟢 Free

The Question

Consider the Latimer diagram for a hypothetical actinide element \ceAn\ce{An} in aqueous acidic medium (pH=0\text{pH} = 0) at 298 K298\text{ K}:

\ceAnO2+→0.55 V\ceAnO2+→0.35 V\ceAn3+→1.25 V\ceAn2+\ce{AnO2^+} \xrightarrow{0.55\text{ V}} \ce{AnO^{2+}} \xrightarrow{0.35\text{ V}} \ce{An^{3+}} \xrightarrow{1.25\text{ V}} \ce{An^{2+}}

Calculate the standard Gibbs free energy change (ΔG∘\Delta G^\circ) for the following balanced comproportionation reaction:

\ceAnO2+(aq)+2An2+(aq)+4H+(aq)⇌3An3+(aq)+2H2O(l)\ce{AnO2^+(aq) + 2An^{2+}(aq) + 4H+(aq) \rightleftharpoons 3An^{3+}(aq) + 2H2O(l)}

(Given: Faraday's constant F=96500 C mol−1F = 96500\text{ C mol}^{-1})

Options

  • A.

    +154.4 kJ mol−1+154.4\text{ kJ mol}^{-1}

  • B.

    +77.2 kJ mol−1+77.2\text{ kJ mol}^{-1}

  • C.

    +67.55 kJ mol−1+67.55\text{ kJ mol}^{-1}

  • D.

    −154.4 kJ mol−1-154.4\text{ kJ mol}^{-1}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Comproportionation Reversibility|Electrode Potential Sign Conventions|Metal Activity Series Logic

Why This Question Is Tricky

Common Mistakes

This problem tests the student's ability to correctly calculate standard cell potentials from a Latimer diagram using Gibbs free energy additivity, rather than simply adding the potentials (a common trap leading to Option C).

Furthermore, it challenges the intuitive assumption that comproportionation to an intermediate oxidation state is always spontaneous.

By setting the reduction potential of the intermediate (\ceAn3+→\ceAn2+\ce{An^{3+}} \rightarrow \ce{An^{2+}}) higher than the potential forming it (\ceAnO2+→\ceAn3+\ce{AnO2^+} \rightarrow \ce{An^{3+}}), the net Ecell∘E^\circ_{\text{cell}} becomes negative, resulting in a positive ΔG∘\Delta G^\circ.

Students must also correctly identify the number of electrons transferred (n=2n=2) in the balanced overall reaction to compute the correct extensive property ΔG∘\Delta G^\circ (failing to do so leads to Option B).

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterRedox Reactions - Class 11 Part 2
ConceptComproportionation Reversibility
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree