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Question #44147
The Question
Consider the Latimer diagram for a hypothetical actinide element in aqueous acidic medium () at :
Calculate the standard Gibbs free energy change () for the following balanced comproportionation reaction:
(Given: Faraday's constant )
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Comproportionation Reversibility|Electrode Potential Sign Conventions|Metal Activity Series Logic
Why This Question Is Tricky
Common Mistakes
This problem tests the student's ability to correctly calculate standard cell potentials from a Latimer diagram using Gibbs free energy additivity, rather than simply adding the potentials (a common trap leading to Option C).
Furthermore, it challenges the intuitive assumption that comproportionation to an intermediate oxidation state is always spontaneous.
By setting the reduction potential of the intermediate () higher than the potential forming it (), the net becomes negative, resulting in a positive .
Students must also correctly identify the number of electrons transferred () in the balanced overall reaction to compute the correct extensive property (failing to do so leads to Option B).
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Redox Reactions - Class 11 Part 2 |
| Concept | Comproportionation Reversibility |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |