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Question #44163

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The Question

The theoretical dipole moment of pp-nitroaniline, assuming no resonance interaction between the \ce−NH2\ce{-NH2} and \ce−NO2\ce{-NO2} groups, is calculated via vector addition to be 5.0 D5.0\text{ D}. The dipole moment of its pure charge-separated quinoid resonance structure (\ceH2N+=C6H4=NO2−\ce{H2N+ = C6H4 = NO2-}) is estimated to be 25.0 D25.0\text{ D}. In benzene at 298 K298\text{ K}, the observed dipole moment of pp-nitroaniline is 6.2 D6.2\text{ D}. When the solvent is changed to ethanol, intermolecular hydrogen bonding selectively stabilizes the charge-separated state, increasing its contribution to the resonance hybrid by an absolute value of 4.0%4.0\%. Assuming the observed dipole moment is a linear combination of the non-interacting and quinoid forms, what is the observed dipole moment of pp-nitroaniline in ethanol?

Options

  • A.

    7.0 D7.0\text{ D}

  • B.

    7.2 D7.2\text{ D}

  • C.

    5.4 D5.4\text{ D}

  • D.

    6.4 D6.4\text{ D}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Dipole Moment Vector Addition|Aniline Resonance Pitfalls|Hydrogen Bonding Competition

Why This Question Is Tricky

Common Mistakes

The problem tests the understanding of synergistic +M+M and −M-M effects in para-substituted benzenes, which lead to an enhanced dipole moment due to the quinoid resonance structure.

Students must recognize that the observed dipole moment is a linear combination of the contributing resonance structures.

Furthermore, it introduces the 'Hidden Variable' of solvent effects: polar, hydrogen-bonding solvents like ethanol stabilize the charge-separated quinoid form, increasing its resonance contribution.

A common trap is incorrectly calculating the change in dipole moment by directly adding 4%4\% of the quinoid moment (yielding 7.2 D7.2\text{ D}) or assuming H-bonding decreases resonance by tying up the \ce−NH2\ce{-NH2} lone pair (yielding 5.4 D5.4\text{ D}).

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterChemical Bonding and Molecular Structure - Class 11 Part 1
ConceptDipole Moment Vector Addition
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree