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Question #44172
The Question
Consider the trihalides \ce{PF3} and \ce{PCl3} at . Based on Bent's rule and the principles of hybridization, which of the following sets of statements correctly describes their structural and chemical properties?
(I) The lone pair on the phosphorus atom in \ce{PF3} occupies an orbital with a higher fractional s-character than the lone pair in \ce{PCl3}. (II) The bond angle is smaller in \ce{PF3} than in \ce{PCl3}. (III) \ce{PF3} is a stronger -donor (Lewis base) towards hard Lewis acids than \ce{PCl3} because fluorine causes less steric hindrance than chlorine. (IV) In transition metal complexes, \ce{PF3} acts as a stronger -acceptor ligand than \ce{PCl3}.
Options
- A.
I, II, and IV only
- B.
I, III, and IV only
- C.
II, III, and IV only
- D.
I and II only
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Mechanism_Trap
Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.
Concepts Behind This Question
Hybridization in Non-Standard Cases|Electrophile vs Nucleophile|C-X Bond Polarization and Polarizability
Why This Question Is Tricky
Common Mistakes
The problem tests the deep implications of Bent's Rule beyond simple bond angles.
Students often fall into the trap of assuming that all hybridized molecules have identical lone pair characters.
By linking the electronegativity of the substituent to the s-character of the lone pair, the question explores how this hidden variable dictates Lewis basicity.
A common misconception is that \ce{PF3} should be a better Lewis base due to lower steric hindrance from the smaller fluorine atoms, ignoring the dominant electronic effect where the high s-character of the lone pair makes it tightly bound and unavailable for -donation.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Chemical Bonding and Molecular Structure - Class 11 Part 1 |
| Concept | Hybridization in Non-Standard Cases |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |