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Question #44262

Difficulty: 8/10 | 🟢 Free

The Question

Consider the standard electrode potentials E∘(M2+/M)E^\circ(M^{2+}/M) and E∘(M3+/M2+)E^\circ(M^{3+}/M^{2+}) of the 3d transition metals at 298 K298\text{ K}, along with their thermodynamic parameters. Which of the following statements are CORRECT?

I. The E∘(M2+/M)E^\circ(M^{2+}/M) value of \ce{Mn} (−1.18 V-1.18\text{ V}) is more negative than that of \ce{Cr} (−0.90 V-0.90\text{ V}) because both the sublimation enthalpy and the sum of the first two ionization enthalpies (IE1+IE2)(IE_1 + IE_2) are lower for \ce{Mn} than for \ce{Cr}.II.The. II. The E^\circ(M^{2+}/M)valueof\ceNi( value of \ce{Ni} (-0.25\text{ V})ismorenegativethanexpectedfromthegeneraltrendprimarilyduetotheexceptionallyhighnegativehydrationenthalpyof\ceNi(aq)2+,whichcompensatesforitshigh) is more negative than expected from the general trend primarily due to the exceptionally high negative hydration enthalpy of \ce{Ni^{2+}_{(aq)}}, which compensates for its high (IE_1 + IE_2).III.The. III. The E^\circ(M^{2+}/M)valueof\ceZn( value of \ce{Zn} (-0.76\text{ V})ismorenegativethanthatof\ceCu() is more negative than that of \ce{Cu} (+0.34\text{ V})primarilybecausethehydrationenthalpyof\ceZn(aq)2+) primarily because the hydration enthalpy of \ce{Zn^{2+}_{(aq)}} is significantly more negative than that of \ce{Cu^{2+}_{(aq)}}.IV.The. IV. The E^\circ(M^{3+}/M^{2+})valuefor\ceMn( value for \ce{Mn} (+1.57\text{ V})ishighlypositivecomparedto\ceFe() is highly positive compared to \ce{Fe} (+0.77\text{ V})becausetheremovalofthethirdelectronfrom\ceMn2+requiresovercomingalargelossinexchangeenergycomparedto\ceFe2+) because the removal of the third electron from \ce{Mn^{2+}} requires overcoming a large loss in exchange energy compared to \ce{Fe^{2+}}.

Options

  • A.

    I, II, and IV only

  • B.

    I, II, and III only

  • C.

    II, III, and IV only

  • D.

    I and IV only

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Hund’s Rule of Maximum Multiplicity|Screening Effect in Inner Shells|E° (M²⁺/M) Anomalies

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to deconstruct the thermodynamic components (Born-Haber cycle) governing standard electrode potentials.

A major trap is assuming that Mn has a higher (IE1 + IE2) than Cr due to its stable 4s2 3d5 configuration, overlooking that Cr's IE2 involves breaking a half-filled 3d5 core.

Another trap is assuming Zn's anomalous potential is driven by a high hydration energy of the d10 ion, whereas Cu2+ actually has a more negative hydration energy due to Jahn-Teller distortion.

Finally, it rigorously tests the quantum mechanical origin (exchange energy) of the 3rd ionization enthalpy differences between Mn and Fe.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterStructure of Atom - Class 11 Part 1
ConceptHund’s Rule of Maximum Multiplicity
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree