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Question #44288
The Question
The Lanthanide Contraction, driven by the poor shielding of electrons, profoundly alters the expected periodic trends in the transition series. However, the magnitude of this anomaly is not static across the -block. Consider the highest oxidation state ions of Group 4 (), Group 5 (), and Group 6 (). Assuming a coordination number of 6 for all species, which of the following correctly represents the relationship between the ionic radii () of these homologous pairs?
Options
- A.
; ;
- B.
; ;
- C.
; ;
- D.
; ;
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Mechanism_Trap
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Concepts Behind This Question
Atomic vs Ionic Radii|Isoelectronic Energy Ordering|Quantum Number Constraints
Why This Question Is Tricky
Common Mistakes
Students commonly memorize the Lanthanide Contraction as a static rule, assuming that 4d and 5d homologous pairs are always identical in size (e.g., , ).
This problem tests the 'Hidden Variable' of differential contraction rates.
Because the 4d series has a lower baseline atomic number, the addition of protons across the period represents a larger fractional increase in compared to the 5d series.
Consequently, the 4d series shrinks faster, creating a 'crossover' effect where the 5d ion starts smaller (Group 4), becomes equal (Group 5), and ends up larger (Group 6) than its 4d counterpart.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Classification of Elements and Periodicity in Properties - Class 11 Part 1 |
| Concept | Atomic vs Ionic Radii |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |