Before You Begin
Question #44336
The Question
A metal forms two sparingly soluble salts, and , with anions and . The standard reduction potential of the electrode is at . The anions and have identical ionic radii and hydration enthalpies. However, due to the higher polarizability of , the standard Gibbs free energy of lattice formation () for is more negative than that of due to covalent stabilization (Fajans' rule).
If the solubility product of is at , what is the standard reduction potential of the electrode?
(Given: , , )
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Numerical_Precision
Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.
Concepts Behind This Question
Fajans' Rule Polarization Power|Electrode Potential Dependencies|Gibbs Energy and Spontaneity
Why This Question Is Tricky
Common Mistakes
This question tests the intersection of Fajans' rule (polarization) and electrochemistry.
Students often memorize standard reduction potentials or Nernst equations without understanding the thermodynamic cycles behind them.
The 'Hidden Variable' here is how the covalent character in a solid lattice (polarization) stabilizes the solid state, thereby decreasing its solubility product ().
This stabilization directly alters the Gibbs free energy of the half-reaction, shifting the reduction potential to a more negative value.
Failing to account for the thermodynamic stabilization of the lattice leads to incorrect values.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Chemical Bonding and Molecular Structure - Class 11 Part 1 |
| Concept | Fajans' Rule Polarization Power |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |