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Question #44384
The Question
Consider the acid dissociation of -nitrophenol (I) and -nitrophenol (II) at . Let and represent their respective acid dissociation constants. Which of the following correctly identifies the relative acidity order in water (polar protic solvent) versus benzene (non-polar aprotic solvent)?
Options
- A.
Water: ; Benzene:
- B.
Water: ; Benzene:
- C.
Water: ; Benzene:
- D.
Water: ; Benzene:
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Phenol Acidity vs. Substituents|Basicity-Solvation Competition|Inductive Effect Trends
Why This Question Is Tricky
Common Mistakes
Students often memorize that p-nitrophenol is more acidic than o-nitrophenol due to the intramolecular hydrogen bond 'trapping' the proton in the ortho isomer.
However, they fail to recognize that acidity is a thermodynamic competition heavily dependent on solvent stabilization of the conjugate base.
In water, the p-nitrophenoxide anion is extensively solvated, making (II) more acidic.
In non-polar solvents, external solvation is absent.
Here, the intrinsic stability of the anion governs acidity.
The o-nitrophenoxide anion is significantly stabilized by the strong electrostatic attraction between the phenoxide oxygen and the adjacent positively charged nitrogen of the nitro group, along with a stronger inductive (-I) effect.
This intrinsic stabilization outweighs the energy cost of breaking the intramolecular H-bond, flipping the acidity order so that (I) > (II) in aprotic media.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Alcohols, Phenols, and Ethers - Class 12 |
| Concept | Phenol Acidity vs. Substituents |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |