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Question #44390
The Question
Consider the following two independent reaction sequences:
\textbf{Sequence 1:} 3-Methoxyphenol is treated with aqueous \ce{NaOH}. The mixture is evaporated to dryness, and the resulting solid is heated at under of \ce{CO2} gas. Subsequent acidification with dilute \ce{HCl} yields \textbf{X} as the major product.
\textbf{Sequence 2:} 4-Nitrophenol is treated with aqueous \ce{NaOH}. The mixture is evaporated to dryness, and the resulting solid is heated at under of \ce{CO2} gas. Subsequent acidification with dilute \ce{HCl} yields \textbf{Y} as the major product.
Identify the major products \textbf{X} and \textbf{Y}.
Options
- A.
\textbf{X} = 2-Hydroxy-4-methoxybenzoic acid; \textbf{Y} = 4-Nitrophenol
- B.
\textbf{X} = 2-Hydroxy-4-methoxybenzoic acid; \textbf{Y} = 2-Hydroxy-5-nitrobenzoic acid
- C.
\textbf{X} = 2-Hydroxy-6-methoxybenzoic acid; \textbf{Y} = 2-Hydroxy-5-nitrobenzoic acid
- D.
\textbf{X} = 4-Hydroxy-2-methoxybenzoic acid; \textbf{Y} = 4-Nitrophenol
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Kolbe-Schmitt Reaction Mechanism|Phenol Acidity vs. Substituents
Why This Question Is Tricky
Common Mistakes
The question tests the critical distinction between thermodynamic acidity and kinetic nucleophilicity in Electrophilic Aromatic Substitution (EAS).
A common student trap is assuming that because strong electron-withdrawing groups (EWGs) like \ce{-NO2} increase phenol acidity (facilitating phenoxide formation), they should enhance Kolbe-Schmitt reactivity.
In reality, the and effects of the \ce{-NO2} group drastically reduce the nucleophilicity of the aromatic ring, making the rate-determining attack on \ce{CO2} kinetically unfeasible, thus halting the reaction.
Additionally, the problem tests regioselectivity in 3-methoxyphenol, requiring the evaluation of synergistic electronic effects and steric hindrance to correctly identify the major ortho-isomer.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Alcohols, Phenols, and Ethers - Class 12 |
| Concept | Kolbe-Schmitt Reaction Mechanism |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |