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Question #44493

Difficulty: 8/10 | 🟢 Free

The Question

Consider the following reaction sequence for 1-methylcyclohex-1-ene (Compound \textbf{A}): A→0∘CBH3⋅THFB→diglymeΔ,160∘CC→H2OH2O2,NaOHD\textbf{A} \xrightarrow[0^\circ\text{C}]{\text{BH}_3 \cdot \text{THF}} \textbf{B} \xrightarrow[\text{diglyme}]{\Delta, 160^\circ\text{C}} \textbf{C} \xrightarrow[\text{H}_2\text{O}]{\text{H}_2\text{O}_2, \text{NaOH}} \textbf{D} Identify the major product \textbf{D}.

Options

  • A.

    trans-2-Methylcyclohexan-1-ol

  • B.

    Cyclohexylmethanol

  • C.

    1-Methylcyclohexan-1-ol

  • D.

    Cycloheptanol

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

Hydroboration-Oxidation Logic|Steric Hindrance (B-Strain)

Why This Question Is Tricky

Common Mistakes

This problem tests the distinction between kinetic and thermodynamic control in hydroboration.

Students typically memorize the 'Textbook Rule' that hydroboration-oxidation yields the anti-Markovnikov alcohol (trans-2-methylcyclohexanol).

However, they often overlook the 'Hidden Variable' of thermal isomerization.

At elevated temperatures (160∘C160^\circ\text{C}), organoboranes undergo reversible dehydroboration, allowing the boron atom to migrate to the least sterically hindered position to relieve B-strain.

The thermodynamic sink is the primary exocyclic carbon, leading to an unexpected regioselectivity that yields cyclohexylmethanol.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterHydrocarbons - Class 11 Part 2
ConceptHydroboration-Oxidation Logic
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree