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Question #44518
The Question
An aqueous solution of ethanol (\ce{C2H5OH}) exhibits a positive deviation from Raoult's Law, forming a minimum-boiling azeotrope at a specific liquid mole fraction and temperature under a constant pressure . Let and represent the integral enthalpy and entropy of vaporization of the azeotropic mixture. Let and be the activity coefficients of ethanol and water in the liquid phase, and and be their respective pure component vapor pressures at . Assuming the vapor phase behaves ideally, which of the following sets of thermodynamic relations is strictly valid during the reversible, isobaric vaporization of this azeotrope?
Options
- A.
, \quad , \quad
- B.
, \quad , \quad
- C.
, \quad , \quad
- D.
, \quad , \quad
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Exception_Exposure
Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.
Concepts Behind This Question
Raoult’s Law Ideal vs Non-Ideal|Entropy of Phase Change|Enthalpy Definition
Why This Question Is Tricky
Common Mistakes
This problem tests the 'Chemical Exception' of azeotropic mixtures behaving as pseudo-pure substances.
Students often conflate the integral properties of mixing (, ) with the localized phase transition properties at the azeotrope.
The trap assumes that because the solution is non-ideal, the entropy of vaporization must be modified by or .
Furthermore, it tests the rigorous application of Raoult's Law at the azeotrope to derive the inverse relationship between activity coefficients and pure vapor pressures, catching students who guess the direct ratio or assume ideality.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Solutions - Class 12 |
| Concept | Raoult’s Law Ideal vs Non-Ideal |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |