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Question #44563

Difficulty: 8/10 | 🟢 Free

The Question

Consider the thermodynamic and spectroscopic profile of the following ligand exchange equilibrium in an aqueous medium at 1 atm1\text{ atm}:

\ce[Co(H2O)6]2+(aq)+4Cl−(aq)<=>[CoCl4]2−(aq)+6H2O(l)\ce{[Co(H2O)6]^2+ (aq) + 4Cl^- (aq) <=> [CoCl4]^2- (aq) + 6H2O (l)}

Upon heating the solution from 298 K298\text{ K} to 350 K350\text{ K}, the color transitions from pale pink to intense deep blue. Identify the correct set of statements regarding this transformation:

I. The forward reaction is entropically driven (ΔS∘>0\Delta S^\circ > 0) due to the release of water molecules, which compensates for the endothermic enthalpy change (ΔH∘>0\Delta H^\circ > 0) at higher temperatures. II. The intense deep blue color of the product is primarily attributed to an increase in the magnitude of the Crystal Field Splitting Energy (CFSE) upon replacing \ceH2O\ce{H2O} with \ceCl−\ce{Cl^-}. III. The d-d transitions in the blue complex are Laporte partially allowed due to p-d orbital mixing in a non-centrosymmetric geometry, leading to a higher molar extinction coefficient (ϵ\epsilon). IV. The spin-only magnetic moment (μs\mu_s) increases significantly because the complex transitions from a low-spin octahedral to a high-spin tetrahedral geometry. V. The endothermicity of the forward reaction is heavily influenced by the high desolvation energy of the \ceCl−\ce{Cl^-} ions and the cleavage of six \ceCo−O\ce{Co-O} bonds.

Options

  • A.

    I, III, and V

  • B.

    I, II, and IV

  • C.

    II, III, and V

  • D.

    I, IV, and V

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Hydrate and Ionization Isomerism|Color and d-d Transitions|Hydrate Stability vs. Carbonyl

Why This Question Is Tricky

Common Mistakes

This question tests the 'Thermodynamic vs.

CFT' trap in coordination chemistry.

Students frequently misattribute the intense color change of transition metal complexes to an increase in ligand field strength or CFSE.

The hidden variable here is that the CFSE actually decreases due to the weaker chloride ligand and tetrahedral geometry.

The intense color arises from the relaxation of the Laporte selection rule (loss of the inversion center).

Additionally, it probes the thermodynamic intuition that ligand exchange from a higher to a lower coordination number is entropically driven but enthalpically penalized due to the hidden costs of ion desolvation and bond cleavage.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterCoordination Compounds - Class 12
ConceptHydrate and Ionization Isomerism
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree