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Question #44568
The Question
Consider the solvolysis of (2S)-3-methyl-2-butyl tosylate (labeled with at the sulfonyl oxygens) in anhydrous trifluoroacetic acid () at . At conversion, the unreacted starting material is recovered and found to exhibit extensive scrambling into the alkyl oxygen position. The product mixture consists of a major rearranged product (A) and a minor unrearranged product (B). Based on the Reaction Progress Coordinate and ion-pair dynamics, which of the following statements correctly identifies the kinetic bottleneck and the stereochemistry of product B?
Options
- A.
The formation of the intimate ion pair (IIP) is the rate-determining step (RDS); product B is a racemic mixture because the secondary carbocation local minimum is long-lived.
- B.
The formation of the IIP is a rapid pre-equilibrium, making the 1,2-hydride shift the RDS for the major pathway; product B exhibits predominantly inversion of configuration (2R).
- C.
The RDS is the solvent collapse from the solvent-separated ion pair (SSIP); product B exhibits predominantly retention of configuration (2S) due to front-side attack.
- D.
The highest energy transition state is the initial ionization; the extensive scrambling indicates thermodynamic control, yielding product B with net retention (2S).
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Mechanism_Trap
Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.
Concepts Behind This Question
Reaction Progress Coordinate|E1/E2 Solvent and Base Effects|Steric Hindrance in SN2
Why This Question Is Tricky
Common Mistakes
This question tests the Winstein ion-pair mechanism and targets the common misconception that the initial ionization in an reaction is always the Rate-Determining Step (RDS).
Extensive isotopic scrambling proves that internal return from the Intimate Ion Pair (IIP) is faster than product formation, making ionization a rapid pre-equilibrium and shifting the RDS to the subsequent 1,2-hydride shift.
Additionally, it tests the stereochemical trap that unrearranged products derived from an IIP do not racemize but undergo inversion due to front-face shielding by the leaving group.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Chemical Kinetics - Class 12 |
| Concept | Reaction Progress Coordinate |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |