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Question #44568

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The Question

Consider the solvolysis of (2S)-3-methyl-2-butyl tosylate (labeled with \ce18O\ce{^{18}O} at the sulfonyl oxygens) in anhydrous trifluoroacetic acid (\ceCF3COOH\ce{CF3COOH}) at 298 K298 \text{ K}. At 30%30\% conversion, the unreacted starting material is recovered and found to exhibit extensive \ce18O\ce{^{18}O} scrambling into the alkyl oxygen position. The product mixture consists of a major rearranged product (A) and a minor unrearranged product (B). Based on the Reaction Progress Coordinate and ion-pair dynamics, which of the following statements correctly identifies the kinetic bottleneck and the stereochemistry of product B?

Options

  • A.

    The formation of the intimate ion pair (IIP) is the rate-determining step (RDS); product B is a racemic mixture because the secondary carbocation local minimum is long-lived.

  • B.

    The formation of the IIP is a rapid pre-equilibrium, making the 1,2-hydride shift the RDS for the major pathway; product B exhibits predominantly inversion of configuration (2R).

  • C.

    The RDS is the solvent collapse from the solvent-separated ion pair (SSIP); product B exhibits predominantly retention of configuration (2S) due to front-side attack.

  • D.

    The highest energy transition state is the initial ionization; the extensive scrambling indicates thermodynamic control, yielding product B with net retention (2S).

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Reaction Progress Coordinate|E1/E2 Solvent and Base Effects|Steric Hindrance in SN2

Why This Question Is Tricky

Common Mistakes

This question tests the Winstein ion-pair mechanism and targets the common misconception that the initial ionization in an SN1S_N1 reaction is always the Rate-Determining Step (RDS).

Extensive isotopic scrambling proves that internal return from the Intimate Ion Pair (IIP) is faster than product formation, making ionization a rapid pre-equilibrium and shifting the RDS to the subsequent 1,2-hydride shift.

Additionally, it tests the stereochemical trap that unrearranged products derived from an IIP do not racemize but undergo inversion due to front-face shielding by the leaving group.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterChemical Kinetics - Class 12
ConceptReaction Progress Coordinate
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree