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Question #44569

Difficulty: 8/10 | 🟢 Free

The Question

Consider three consecutive 3d transition metals M1M_1, M2M_2, and M3M_3 (where atomic numbers follow Z1<Z2<Z3Z_1 < Z_2 < Z_3). The standard reduction potential E∘(M2+/M)E^\circ(M^{2+}/M) for M2M_2 is anomalously more negative than the expected trend between M1M_1 and M3M_3. M1M_1 and M3M_3 form stable neutral mononuclear carbonyls M1(CO)xM_1(CO)_x and M3(CO)yM_3(CO)_y that strictly obey the 18-electron rule. M2M_2 forms a stable homoleptic binuclear carbonyl (M2)2(CO)z(M_2)_2(CO)_z but no stable neutral mononuclear carbonyl.

Evaluate the following statements: \begin{enumerate} \item[I.] The anomalous E∘(M2+/M)E^\circ(M^{2+}/M) of M2M_2 is primarily driven by the exchange energy stabilization of M22+M_2^{2+} and its low enthalpy of atomization. \item[II.] M2M_2 fails to form a stable neutral mononuclear carbonyl because its half-filled d-subshell completely inhibits π\pi-backdonation. \item[III.] The C-O stretching frequency in the cationic complex [M2(CO)x]+[M_2(CO)_x]^+ is higher than in M1(CO)xM_1(CO)_x. \item[IV.] The metal-carbon bond length in [M2(CO)y]−[M_2(CO)_y]^- is shorter than in M3(CO)yM_3(CO)_y. \end{enumerate}

How many of the above statements are CORRECT?

Options

  • A.

    1

  • B.

    2

  • C.

    3

  • D.

    4

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Exception_Exposure

Learn to identify edge cases and boundary exceptions that JEE examiners hide in math problems.

Concepts Behind This Question

E° (M²⁺/M) Anomalies|Synergic Bonding in Carbonyls|Color and d-d Transitions

Why This Question Is Tricky

Common Mistakes

The question tests the intersection of thermodynamic anomalies in the d-block and the principles of synergic bonding in coordination chemistry.

Students often misattribute the E∘E^\circ anomaly of Mn to hydration enthalpy (which is actually less negative due to zero CFSE for high-spin d5d^5) or fail to recognize the role of atomization energy.

Furthermore, the trap lies in correlating the stability of the d5d^5 ion with a lack of backbonding capability (Statement II), ignoring that carbonyl stability is governed by the 18-electron rule.

Finally, it rigorously tests the effect of effective nuclear charge (ZeffZ_{eff}) on isoelectronic complexes, requiring students to correctly deduce that higher ZeffZ_{eff} weakens M-C π\pi-bonding but strengthens the C-O bond (Statement III), while lower ZeffZ_{eff} strengthens the M-C bond (Statement IV).

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterD and F Block Elements - Class 12
ConceptE° (M²⁺/M) Anomalies
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree