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Question #44578
The Question
Pure -D-glucopyranose () is dissolved in an aqueous buffer at 298 K containing a large excess of a transition metal ion, . The ion forms a kinetically inert and thermodynamically highly stable chelate complex (, ) exclusively with the \textit{cis}-1,2-diol system present in -D-glucopyranose (). The -anomer does not coordinate with . Assuming the chelate remains completely intact, what is the final specific rotation of the carbohydrate species in solution at equilibrium, and what is the observation when this final solution is treated with ?
Options
- A.
; Bromine water is not decolorized.
- B.
; Bromine water is decolorized.
- C.
; Bromine water is not decolorized.
- D.
; Bromine water is decolorized.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Mechanism_Trap
Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.
Concepts Behind This Question
Optical Isomerism Logic|D-Glucose Anomeric Equilibrium|Reducing Sugar Criteria
Why This Question Is Tricky
Common Mistakes
This problem tests the intersection of dynamic equilibrium (mutarotation) and coordination chemistry.
Students often rote-memorize that 'glucose is a reducing sugar' and 'glucose mutarotates to '.
The trap is failing to recognize that mutarotation and reducing properties strictly depend on the availability of the free hemiacetal hydroxyl to undergo reversible ring-opening.
By introducing a metal ion that selectively chelates the cis-1,2-diol of the -anomer, the equilibrium is thermodynamically driven to 100% complexation via Le Chatelier's Principle.
Furthermore, the coordinate bond locks the anomeric center, stripping the molecule of its reducing properties.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Coordination Compounds - Class 12 |
| Concept | Optical Isomerism Logic |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |