Start Learning Free

Before You Begin

Question #44586

Difficulty: 8/10 | 🟢 Free

The Question

Consider the following coordination complexes at 298 K: (I) \ce{[Ni(PPh3)2Cl2]} (II) \ce{[Pt(PPh3)2Cl2]} (III) \ce{[Ni(phen)3]^{2+}} (IV) \ce{[Cu(NH3)4]^{2+}} (V) \ce{[Co(ox)3]^{3-}} (VI) \ce{[Fe(H2O)5(NO)]^{2+}}

Let nin_i be the number of unpaired electrons in the ii-th complex. Determine the value of ∑i=16ni\sum_{i=1}^{6} n_i.

Options

  • A.

    6

  • B.

    7

  • C.

    8

  • D.

    9

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Spin-Only Magnetic Moment|Valence Bond Theory Hybridization|Nucleophilic Addition Sterics

Why This Question Is Tricky

Common Mistakes

The problem tests multiple exceptions to standard Valence Bond Theory (VBT) and Crystal Field Theory (CFT). 1) Steric override: Bulky PPh3PPh_3 forces 3d83d^8 Ni2+Ni^{2+} into a tetrahedral geometry, bypassing the expected square planar dsp2dsp^2 hybridization. 2) Heavy metal anomaly: 5d85d^8 Pt2+Pt^{2+} ignores sterics due to massive CFSE, remaining square planar. 3) Octahedral d8d^8 trap: Strong field ligands cannot force pairing in OhOh d8d^8 systems. 4) Oxidation state effect: Co3+Co^{3+} turns the typically weak-field oxalate into a strong-field ligand. 5) Brown ring anomaly: Fe+Fe^+ forms a high-spin d7d^7 complex despite the strong NO+NO^+ ligand.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterCoordination Compounds - Class 12
ConceptSpin-Only Magnetic Moment
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree