Before You Begin
Question #44593
The Question
An optically active, violet-colored coordination compound has the empirical formula (where = ethylenediamine). When a dilute aqueous solution of is maintained at , it undergoes a first-order reaction to form a new complex . During this process, the solution gradually loses its optical activity and its color changes from violet to pinkish-red. Which of the following statements correctly identifies the mechanism responsible for the loss of optical activity and the fundamental cause of the color change?
Options
- A.
Dissociation of a ligand forms a trigonal bipyramidal intermediate leading to stereochemical scrambling, while substitution by increases , shifting the absorption maximum to a shorter wavelength.
- B.
Spontaneous reduction of to creates a labile complex that rapidly racemizes, and the change in oxidation state alters the d-d transition energy.
- C.
Association of forms a chiral pentagonal bipyramidal intermediate that undergoes reductive elimination, decreasing and shifting the absorption maximum to a longer wavelength.
- D.
Isomerization to the thermodynamically stable \textit{trans}-isomer occurs without ligand exchange, and the color change is driven by a transition from a low-spin to a high-spin state.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Mechanism_Trap
Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.
Concepts Behind This Question
Color and d-d Transitions|Optical Isomerism Logic|Valence Bond Theory Hybridization
Why This Question Is Tricky
Common Mistakes
This problem tests the intersection of coordination kinetics, stereochemistry, and Crystal Field Theory.
Students often rely on the heuristic that a dramatic color change coupled with a loss of optical activity implies a redox reaction (e.g., reduction to a labile species).
The 'hidden mechanism' here is the dissociative aquation pathway: the formation of a trigonal bipyramidal intermediate explains the stereochemical scrambling (loss of chirality), while the spectrochemical series () explains the increase in and the subsequent blue-shift in absorption (resulting in a red-shift in transmitted color), entirely without a change in oxidation state.
Quick Facts About This Question
Question Information
| Subject | Chemistry |
| Chapter | Coordination Compounds - Class 12 |
| Concept | Color and d-d Transitions |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |