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Question #44604

Difficulty: 8/10 | 🟢 Free

The Question

Among the 3d transition metals, there exists a unique, neutral, mononuclear homoleptic metal carbonyl complex \ceM(CO)x\ce{M(CO)_x} that is paramagnetic at 298 K and 1 atm, defying the 18-electron rule. It resists dimerization due to severe steric crowding. Based on Crystal Field Theory and synergic bonding principles, determine the spin-only magnetic moment (μspin\mu_{spin}) of this complex and the crystal field electronic configuration of the metal center.

Options

  • A.

    1.73 BM,t2g5eg01.73 \text{ BM}, t_{2g}^5 e_g^0

  • B.

    0.00 BM,t2g6eg00.00 \text{ BM}, t_{2g}^6 e_g^0

  • C.

    3.87 BM,t2g3eg23.87 \text{ BM}, t_{2g}^3 e_g^2

  • D.

    1.73 BM,e4t211.73 \text{ BM}, e^4 t_2^1

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Synergic Bonding in Carbonyls|Spin-Only Magnetic Moment|Tetrahedral Splitting Patterns

Why This Question Is Tricky

Common Mistakes

This problem tests the intersection of the 18-electron rule, synergic bonding, and Crystal Field Theory.

The primary trap is the 'Low Spin = Diamagnetic' heuristic.

Students often assume all metal carbonyls dimerize to achieve 18 electrons (Option B).

The secondary trap exploits the 'Tetrahedral vs Octahedral' geometry; students might incorrectly assume a tetrahedral geometry (like \ceNi(CO)4\ce{Ni(CO)_4}) and force a strong-field splitting to get 1 unpaired electron (Option D), ignoring that \ceV(CO)6\ce{V(CO)_6} is strictly octahedral.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterCoordination Compounds - Class 12
ConceptSynergic Bonding in Carbonyls
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree