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Question #44624

Difficulty: 8/10 | 🟢 Free

The Question

Consider the following substrates undergoing nucleophilic substitution with \ceNaOCH3\ce{NaOCH3} in \ceCH3OH\ce{CH3OH} at 298 K:

(P) 1-chloro-2,4-dinitrobenzene (Q) 1-chloro-3,5-dimethyl-2,4-dinitrobenzene (U) 1-chloro-4-nitrobenzene (R) 1-bromo-2,2-dimethylpropane (S) 1-bromobutane

Let Ea,PE_{a,P}, Ea,QE_{a,Q}, and Ea,UE_{a,U} be the activation energies for the SNAr\text{S}_\text{N}\text{Ar} reactions of P, Q, and U respectively. Let Ea,RE_{a,R} and Ea,SE_{a,S} be the activation energies for the SN2\text{S}_\text{N}2 reactions of R and S respectively.

Which of the following correctly orders the activation energies, reflecting the dominant transition state electronic and steric effects?

Options

  • A.

    Ea,P<Ea,U<Ea,QE_{a,P} < E_{a,U} < E_{a,Q} and Ea,S<Ea,RE_{a,S} < E_{a,R}

  • B.

    Ea,P<Ea,Q<Ea,UE_{a,P} < E_{a,Q} < E_{a,U} and Ea,S<Ea,RE_{a,S} < E_{a,R}

  • C.

    Ea,Q<Ea,P<Ea,UE_{a,Q} < E_{a,P} < E_{a,U} and Ea,R<Ea,SE_{a,R} < E_{a,S}

  • D.

    Ea,U<Ea,P<Ea,QE_{a,U} < E_{a,P} < E_{a,Q} and Ea,S<Ea,RE_{a,S} < E_{a,R}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Mechanism_Trap

Don't get tricked by the process! Learn the mechanical traps used in competitive exam questions.

Concepts Behind This Question

Steric Hindrance in SN2|Nucleophilic Aromatic Substitution (SNAr)

Why This Question Is Tricky

Common Mistakes

The question tests the student's ability to distinguish between two distinct types of steric effects in nucleophilic substitutions.

In SN2\text{S}_\text{N}2 reactions (aliphatic), steric bulk directly blocks the kinetic trajectory of the incoming nucleophile, drastically increasing EaE_a (as seen in neopentyl systems).

In SNAr\text{S}_\text{N}\text{Ar} reactions (aromatic), the nucleophile attacks perpendicular to the ring, so trajectory blocking is minimal.

However, bulky groups ortho to an electron-withdrawing group (like −NO2-\text{NO}_2) force it out of coplanarity with the ring.

This 'Steric Inhibition of Resonance' (SIR) prevents the −NO2-\text{NO}_2 group from stabilizing the Meisenheimer complex via the −M-\text{M} effect.

Students often fall into the trap of counting the number of −NO2-\text{NO}_2 groups (assuming Q > U) without accounting for their 3D spatial orientation and the resulting loss of electronic activation.

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterHaloalkanes and Haloarenes - Class 12
ConceptSteric Hindrance in SN2
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree