Start Learning Free

Before You Begin

Question #44649

Difficulty: 8/10 | 🟢 Free

The Question

An aqueous solution is prepared by dissolving 2525 g of \ce{K3[Fe(CN)6]} (Molar mass =329= 329 g mol−1^{-1}) in 1.0×1021.0 \times 10^2 g of water. The experimental freezing point of this solution is measured to be −3.6∘C-3.6^\circ\text{C}.

Assuming the Van't Hoff factor (ii) remains constant over the temperature range, calculate the experimental Van't Hoff factor (ii) to the correct number of significant figures, and the expected boiling point of the solution at 11 atm.

(Given: Kf=1.86K_f = 1.86 K kg mol−1^{-1}, Kb=0.512K_b = 0.512 K kg mol−1^{-1}, normal boiling point of water is exactly 100∘C100^\circ\text{C})

Options

  • A.

    i=2.5i = 2.5, Tb=100.99∘CT_b = 100.99^\circ\text{C}

  • B.

    i=2.5i = 2.5, Tb=100.97∘CT_b = 100.97^\circ\text{C}

  • C.

    i=4.0i = 4.0, Tb=101.6∘CT_b = 101.6^\circ\text{C}

  • D.

    i=2.6i = 2.6, Tb=101.0∘CT_b = 101.0^\circ\text{C}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Numerical_Precision

Improve calculation stamina and avoid rounding errors in high-stakes competitive examinations.

Concepts Behind This Question

Significant Figures in Arithmetic|Van’t Hoff Factor (i) Application

Why This Question Is Tricky

Common Mistakes

The problem tests two critical concepts: 1) High Concentration Non-Ideality: At high concentrations, strong electrolytes like \ce{K3[Fe(CN)6]} deviate significantly from their ideal Van't Hoff factor (i=4i=4) due to ion pairing. 2) Significant Figures and Premature Rounding: Students must report the final value of ii to 2 significant figures (2.52.5).

However, a common trap is using this rounded value in subsequent calculations.

According to strict significant figure rules, intermediate values must not be rounded.

Using the exact ii (or the direct ratio ΔTb/ΔTf\Delta T_b / \Delta T_f) yields a boiling point of 100.99∘C100.99^\circ\text{C}, whereas using the rounded ii yields 100.97∘C100.97^\circ\text{C}.

Additionally, it traps students who perform incorrect sequential rounding (2.547→2.55→2.62.547 \rightarrow 2.55 \rightarrow 2.6).

Quick Facts About This Question

Question Information

SubjectChemistry
ChapterSome Basic Concepts of Chemistry - Class 11 Part 1
ConceptSignificant Figures in Arithmetic
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree